Python 如何按原样比较两个两位数整数、反向整数和一次比较一个字符

我是编程新手，正在尝试通过使用python学习入门课程来学习编程

我的一项任务要求我们做以下工作：

将随机生成的两位数整数与用户生成的两位数整数进行比较

如果随机整数和用户生成的整数都匹配，则打印blah1

如果用户生成的整数与随机生成的整数的两位数相反，则打印blah2

如果用户生成的整数有一个数字与随机生成的整数相同，请打印blah3

现在，到目前为止，我们只学习了基本的东西，（操作符，

if

/

else

/

elif

，

while

循环、打印、字符串、整数）

我想出了一种方法，随机分配两个数字，将它们转换成字符串，然后将它们连接成一个两位数的字符串。从这里开始，我使用

elif

语句来匹配每个可能的条件

不幸的是，这不是必需的。当我进行比较时，我必须使用两位整数。不幸的是，我完全不知道如何比较整数的各个部分，或者如何将整数与我所学的进行反转

现在，我不是在找人帮我解决这个问题。我需要一些帮助，或者是一个提示，或者是一个建议，告诉我应该如何用我的基本知识来思考这个问题

非常感谢您的任何帮助

我已经包括了我写的代码

# homework 2
# problem 1
#
# lottery guessing program
#
# the program randomly generates a two-digit number, prompts the user to enter a two-digit number,
# and determines whether the user wins according to the following rules:
#
# 1. if both digits match in the right order, you will win $10,000.
# 2. if both digits match, but in the reversed order, you will win $3,000.
# 3. if you match one digit in either place, you will win $1,000

#imports
import random

#rules
print("guess a number.  if both digits match in the right order, you will win $10,000."\
      "\nif both digits match, but in the reversed order, you will win $3,000." \
      "\nif you match one digit in either place, you will win $1,000." \
      "\nif you don't match any digits, you do not win anything.")

# random variables
rand_num1 = str(random.randint(1,9))
rand_num2 = str(random.randint(1,9))

#ask user for number
user_num1 = input("what is your first number? ")
user_num2 = input("what is your second number? ")

#for testing purposes, if testing, comment out the previous two lines
#combd_num = (str(rand_num1)) + (str(rand_num2))
#revsd_num = (str(rand_num2)) + (str(rand_num1))
#print(rand_num1)
#print(rand_num2)
#print(combd_num)
#print(revsd_num)
#user_num1 = input("what is your first number? ")
#user_num2 = input("what is your second number? ")
#ucomb_num = (str(user_num1)) + (str(user_num2))

#output the numbers
print("the number is, ", (rand_num1 + rand_num2),"\
      \nyour number is, ", (user_num1 + user_num2), sep="")

#elif statement
if (user_num1 + user_num2) == (rand_num1 + rand_num2):
    print("you guessed the exact number.  you win $10,000!")
elif (user_num2 + user_num1) == (rand_num1 + rand_num2):
    print("you guessed both digits but in reverse.  you win $3,000!")
elif user_num1 == rand_num1 and user_num2 != rand_num2:
    print("you guessed one digit right.  you win $1,000!")
elif user_num1 == rand_num2 and user_num2 != rand_num2:
    print("you guessed one digit right.  you win $1,000!")
elif user_num2 == rand_num1 and user_num1 != rand_num2:
    print("you guessed one digit right.  you win $1,000!")
elif user_num2 == rand_num2 and user_num1 != rand_num2:
    print("you guessed one digit right.  you win $1,000!")
else:
    print("sorry, you didn't guess the right number.")

---

我认为您面临的挑战是如何从两位整数中获取独立的数字。使用数学运算符是可能的

想想像

42

这样的数字中的每个数字代表什么。

4

是“十”位，2是“一”位。反过来考虑可能会有所帮助。如果整数

4

和

2

在单独的变量中，如何将它们组合成单个整数

42

---

希望我的提示能帮到你！如果我说得太委婉了，我可以试着详细阐述一下，但我确实希望您能够自己解决这个问题，我想一旦您想到了正确的运算符，您会很快得到它。

这里有三个技巧可以帮助您：

列表可以像字符串和数字一样进行比较。整数列表可以与另一个整数进行比较，如果包含的数字相同，则比较返回

True

：

>>> [1, 2] == [1, 2]
True
>>> [1, 3] == [1, 2]
False

你可以很容易地撤销列表。您可以使用

reversed（）

内置函数，也可以使用

[开始：停止：步幅]

切片表示法给出负步幅。后者也为您提供了一个相反的列表：

>>> list(reversed([1, 2]))
[2, 1]
>>> [1, 2][::-1]
[2, 1]

reversed（）

函数返回一个迭代器，通过将迭代器传递给

list（）

构造函数，我们再次得到一个列表

您可以使用中的

操作符测试列表成员资格。使用此选项测试单个整数是否为整数列表的一部分：

>>> 1 in [1, 2]
True
>>> 3 in [1, 2]
False

这三个技巧结合在一起，将为您提供重新编程脚本以使用整数所需的所有工具。将您的随机数和用户输入（使用

int（）

函数转换为整数）存储在列表中，然后从中开始工作

如果您必须接受10到99之间的一个整数输入，那么事情就变得有点棘手了。您可以使用th模

%

和除法

\

运算符将10和1分开：

ones = number % 10
tens = number // 10

您可以使用以下命令组合这两个操作：

---

现在您又有了两个单独的整数来进行比较。

好的，感谢大家的帮助。由于你的建议和提示，我按照规范完成了作业

然而，我并不为它是如何完成的而感到骄傲——只是在我看来有些草率——它是有效的

这是：

#imports
import random

#rules
print("guess a number.  if both digits match in the right order, you will win $10,000."\
      "\nif both digits match, but in the reversed order, you will win $3,000." \
      "\nif you match one digit in either place, you will win $1,000." \
      "\nif you don't match any digits, you do not win anything.")

#random variable
rand_num = random.randint(0,99)
print(rand_num)
#separate the digits
rand_num_tens = rand_num//10
print(rand_num_tens)
rand_num_ones = rand_num%10
print(rand_num_ones)
#reverse the random number digits
revsd_rnd_num = (rand_num_ones * 10) + rand_num_tens
print(revsd_rnd_num)

#ask user for number
user_num = int(input("guess a number between 1 and 99: "))
#separate the digits
user_num_tens = user_num//10
print(user_num_tens)
user_num_ones = user_num%10
print(user_num_ones)

#output the numbers
print("the number is, ", rand_num,"\
      \nyour number is, ", user_num, sep="")

#elif statement
if rand_num == user_num:
    print("you guessed the exact number.  you win $10,000!")
elif revsd_rnd_num == user_num:
    print("you guessed both digits but in reverse.  you win $3,000!")
elif rand_num_tens == user_num_tens:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_tens == user_num_ones:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_ones == user_num_tens:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_ones == user_num_ones:
    print("you guessed one digit right.  you win $1,000!")
else:
    print("sorry, you didn't guess the right number.")

---

Sameer还可能会发现知道明显的

[1,2]==reversed（[2,1]）

给出了

False

，这很有帮助，您必须使用

[1,2]==list（reversed（[2,1]）

或切片符号来获取列表进行比较。顺便说一句，我不相信您使用

reversed（）

给出的示例的输出。对了，在Python3中，reversed是一个迭代器，我仍然经常使用Python2。我会更正的。Python 2中的

reversed

是否也返回

listreverseiterator对象

？@MartijnPieters:我不知道为什么以前没有注意到整数除法和模运算符。谢谢，差不多做到了。

#imports
import random

#rules
print("guess a number.  if both digits match in the right order, you will win $10,000."\
      "\nif both digits match, but in the reversed order, you will win $3,000." \
      "\nif you match one digit in either place, you will win $1,000." \
      "\nif you don't match any digits, you do not win anything.")

#random variable
rand_num = random.randint(0,99)
print(rand_num)
#separate the digits
rand_num_tens = rand_num//10
print(rand_num_tens)
rand_num_ones = rand_num%10
print(rand_num_ones)
#reverse the random number digits
revsd_rnd_num = (rand_num_ones * 10) + rand_num_tens
print(revsd_rnd_num)

#ask user for number
user_num = int(input("guess a number between 1 and 99: "))
#separate the digits
user_num_tens = user_num//10
print(user_num_tens)
user_num_ones = user_num%10
print(user_num_ones)

#output the numbers
print("the number is, ", rand_num,"\
      \nyour number is, ", user_num, sep="")

#elif statement
if rand_num == user_num:
    print("you guessed the exact number.  you win $10,000!")
elif revsd_rnd_num == user_num:
    print("you guessed both digits but in reverse.  you win $3,000!")
elif rand_num_tens == user_num_tens:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_tens == user_num_ones:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_ones == user_num_tens:
    print("you guessed one digit right.  you win $1,000!")
elif rand_num_ones == user_num_ones:
    print("you guessed one digit right.  you win $1,000!")
else:
    print("sorry, you didn't guess the right number.")