如何检查两个目录中的相同文件名是否匹配，并使用python将其追加？

我有两个目录和多个文件（读为CSV）。文件名表示特定的客户编号。 我阅读了以下文件

我以CSV格式读取这些文件

如果directory2文件名（文件）与directory1中的文件名匹配，则我希望将数据作为一个文件附加在一起

如果文件名（文件）不在directory1中，则按原样复制数据

此新文件应保存到新目录中

---

你能试一下吗

import os
import glob
import shutil

dir1 = "/path/to/dir1/"
dir2 = "/path/to/dir2/"
new_dir = "/path/to/dir3/"
fpaths_dir1 = glob.glob(os.path.join(dir1, '*.csv'))
fpaths_dir1 = [os.path.basename(fpath) for fpath in fpaths_dir1]
fpaths_dir2 = glob.glob(os.path.join(dir2, '*.csv'))
fpaths_dir2 = [os.path.basename(fpath) for fpath in fpaths_dir2]

for fpath in fpaths_dir1:
    if fpath in fpaths_dir2:
        f1 = os.path.join(dir1, fpath)
        f2 = os.path.join(dir2, fpath)
        # write your code to open both files
        # and contatenate
    else:
        f1 = os.path.join(dir1, fpath)
        f3 = os.path.join(new_dir, fpath)
        shutil.copyfile(f1, f3)

---

将数据作为一个文件附加在一起

我将其留给您，如果有任何问题，请告诉我。

如何在1000个文件中打开两个匹配的文件名？

f1

和

f2

是匹配的文件，您只需将这些文件连接起来即可

import os
import glob
import shutil

dir1 = "/path/to/dir1/"
dir2 = "/path/to/dir2/"
new_dir = "/path/to/dir3/"
fpaths_dir1 = glob.glob(os.path.join(dir1, '*.csv'))
fpaths_dir1 = [os.path.basename(fpath) for fpath in fpaths_dir1]
fpaths_dir2 = glob.glob(os.path.join(dir2, '*.csv'))
fpaths_dir2 = [os.path.basename(fpath) for fpath in fpaths_dir2]

for fpath in fpaths_dir1:
    if fpath in fpaths_dir2:
        f1 = os.path.join(dir1, fpath)
        f2 = os.path.join(dir2, fpath)
        # write your code to open both files
        # and contatenate
    else:
        f1 = os.path.join(dir1, fpath)
        f3 = os.path.join(new_dir, fpath)
        shutil.copyfile(f1, f3)