Python 如何使代码循环并将以前的结果与新结果相加

所以我的问题是： 编写一个程序，要求用户输入两个数字。数字 应添加并显示总和。然后程序将询问 用户是否希望继续输入。如果他或她 回答“是”或“是”，程序将要求用户重新输入两个 然后再次计算总和（总和将累加）。
否则，程序将终止

现在我掌握的代码是：

number1 = int(input("Please enter the first number: "))
number2 = int(input("Please enter the second number: "))
result = number1 + number2
print("\nThe sum is:", result)

while True:
   a = input("Do you want to continue (Yes or No): ").lower()
   if a == "yes":
       print(
  
   elif a == "no":
       print(
       break

---

但是我不知道如何再次要求用户输入两个新的数字，然后将它们添加到以前的结果中。

您几乎已经得到了它。只需将输入移动到循环内部，并将结果存储在循环外部：

result = 0

while True:
    number1 = int(input("Please enter the first number: "))
    number2 = int(input("Please enter the second number: "))

    result = result + number1 + number2

    print("\nThe sum is:", result)

    a = input("Do you want to continue (Yes or No): ").lower()
    if a != "yes":
       break

---

因为您想继续输入，所以

input

语句应该进入

while

循环中。此外，应初始化

result

变量以进行更新。如果答案是

yes

，您可以在

if

条件中添加

continue

，以

重新启动

while循环。此外，即使不编写

yes

或

no

，程序也会运行。为了解决这个问题，我们可以添加一个

else

语句。以下是更新的代码：

result=0 #initializing the 'result' variable
while True:
   number1 = int(input("Please enter the first number: "))
   number2 = int(input("Please enter the second number: "))
   result += number1 + number2 #updating the result
   print("\nThe sum is:", result )
   a = input("Do you want to continue (Yes or No): ").lower()
   if a == "yes":
      continue #continuing the loop if the answer is yes
   elif a == "no":
       print("bye")
       break
   else:
      print("wrong input !! please try again")
      a = input("Do you want to continue (Yes or No): ").lower()

测试：

Please enter the first number: 2
Please enter the second number: 2

The sum is: 4
Do you want to continue (Yes or No): ll
wrong input !! please try again
Do you want to continue (Yes or No): yes
Please enter the first number: 2
Please enter the second number: 2

The sum is: 8
Do you want to continue (Yes or No): no
bye

---

添加了一个答案，希望能有所帮助。