Python 如果，elif&；！=，==布尔运算仅返回“0”；假；有投入

我正在创建一个interwes-ripoff（为了好玩！），while-True&if/elif/else语句只会返回false（而不是冒名顶替者）。我已经为这些名字创建了一个列表，列表中的两个随机元素将被选为冒名顶替者。但是，每当我输入的名称是冒名顶替者时，它只会返回

（玩家）不是骗子

这是我的密码

import sys, time, random
names = ["player1", "player2", "player3", "player4", "player5", "player6", "player7", "player8", "player9", "player10"]
print("Players: ")
for x in names:
  print(x)
print('—————————————————————————')
impostor1 = random.choice(names)
impostor2 = random.choice(names)
crewmates = 8
impostors = 2
tries = 6
while True:
  talk = input("Guess who The Impostor(s) are. " + str(crewmates) + " Crewmates are left. " + str(impostors) + " Impostors are left. You have " + str(tries) + " tries left.")
  if talk in names:
    print(talk + " was voted for.")
    time.sleep(0.1)
    if talk != impostor1 or talk != impostor2:
      notimp = talk + " was not An Impostor. "
      names.remove(talk)
      for y in notimp:
        sys.stdout.write(y)
        sys.stdout.flush()
        time.sleep(0.05)
      crewmates -= 1
      tries -= 1
    elif talk == impostor1 or talk == impostor2:
      wasimp = talk + " was An Impostor. "
      names.remove(talk)
      for v in wasimp:
        sys.stdout.write(v)
        sys.stdout.flush()
        time.sleep(0.1)
      impostors -= 1
  else:
    print("That player was either ejected or is not a valid player.")

---

但是，每当我在输入中输入冒名顶替者时，它都会说它不是冒名顶替者？

我认为这一行是问题的根源：

if talk！=冒名顶替者1或交谈！=冒名顶替者2:

假设

impositor1

是player1，

impositor2

是player2，根据Python

Boolean

expression操作符

或
if
语句的计算结果如下：

if player1！=impostor1
计算为
False
，因为player1实际上等于
impostor1

到目前为止还不错，但因为第一个测试是
False
，Python只计算并返回右侧操作数，该操作数可以是
True
或
False
。在您的情况下，Python将对if talk！=impostor2

并返回

True

，然后执行嵌套块。

哦，如果您需要更干净的代码版本，我可以提供。我只需要知道这些if语句的错误，我不需要重写代码。请提供预期的结果。显示中间结果与预期结果的偏差。我们应该能够将单个代码块粘贴到文件中，运行它，并重现您的问题。你为一个三行问题发布了30行代码。