在python 3.3中从.txt向收件人发送电子邮件
我正在尝试使用python 3.3中的smtp向文本文件中列出的收件人发送电子邮件。 我收到的错误是:在python 3.3中从.txt向收件人发送电子邮件,python,python-3.x,smtp,smtplib,Python,Python 3.x,Smtp,Smtplib,我正在尝试使用python 3.3中的smtp向文本文件中列出的收件人发送电子邮件。 我收到的错误是: session.sendmail(发件人、收件人、msg.as\u string()) smtplib.smtprecipientsreference:{} sendmail中的错误在哪里?谢谢 完整代码如下: #!/usr/bin/python import os, re import sys import smtplib from email.mime.image import MIME
session.sendmail(发件人、收件人、msg.as\u string())
smtplib.smtprecipientsreference:{}
sendmail中的错误在哪里?谢谢
完整代码如下:
#!/usr/bin/python
import os, re
import sys
import smtplib
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
mails = open('/path/emails.txt','r+')
mailList = mails.read()
mailList = [i.strip() for i in mails.readlines()]
directory = "/path/Desktop/"
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'Sender@gmail.com'
password = "Sender'sPassword"
recipient = [i.strip() for i in mails.readlines()]
subject = 'Python (-++-) Test'
message = 'Images attached.'
def main():
msg = MIMEMultipart()
msg['Subject'] = 'Python (-++-) Test'
msg['To'] = recipient
msg['From'] = sender
files = os.listdir(directory)
pngsearch = re.compile(".png", re.IGNORECASE)
files = filter(pngsearch.search, files)
for filename in files:
path = os.path.join(directory, filename)
if not os.path.isfile(path):
continue
img = MIMEImage(open(path, 'rb').read(), _subtype="png")
img.add_header('Content-Disposition', 'attachment', filename=filename)
msg.attach(img)
part = MIMEText('text', "plain")
part.set_payload(message)
msg.attach(part)
session = smtplib.SMTP(SMTP_SERVER, SMTP_PORT)
session.ehlo()
session.starttls()
session.ehlo
session.login(sender, password)
session.sendmail(sender, recipient, msg.as_string())
session.quit()
if __name__ == '__main__':
main()
您想再次检查您的收件人代码。看起来您不止一次地尝试使用文件的内容,这是行不通的--文件对象应该被理解为一个流,而不是一个数据块,因此,一旦您执行了
f.read()
或[i.strip()for i in mails.readlines()]
一次,该流就是空的,因此,第二次这样做将产生一个空列表。您应该通过打印收件人
然后试试这个:
mails = open('/path/emails.txt','r+')
#mailList = mails.read()
#mailList = [i.strip() for i in mails.readlines()]
directory = "/path/Desktop/"
SMTP_SERVER = 'smtp.gmail.com'
SMTP_PORT = 587
sender = 'Sender@gmail.com'
password = "Sender'sPassword"
recipient = [i.strip() for i in mails.readlines()]
print(recipient)
subject = 'Python (-++-) Test'
message = 'Images attached.'
现在,您应该有一个已填充的收件人列表,并进入下一期