Python 替换数据帧中的字符串，保持第一次发生的完整性

我有一个熊猫数据框，如下所示：

df
Name    Statement 1
A       Value is favourable due to A favourable due to Q favourable due to U and unfavourable due to D
B       Value is favourable due to T favourable due to W favourable due to J and unfavourable due to O
C       Value is favourable due to U favourable due to D favourable due to H and unfavourable due to P
D       Value is favourable due to J favourable due to F favourable due to M and unfavourable due to Z

是否有任何方法可以将字符串

替换为“

”，“”，除了第一次出现之外

对于不利的部分也需要做同样的事情。

试试以下方法：

df['Statement 1'] = df['Statement 1'].apply(lambda x: x[:27]+x[27:].replace(' favourable due to', ','))

print(df.to_string())

输出：

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

试试这个：

df['Statement 1'] = df['Statement 1'].apply(lambda x: x[:27]+x[27:].replace(' favourable due to', ','))

print(df.to_string())

输出：

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

这将有助于：

df['Statement 1'] = df['Statement 1'].apply(lambda x: x.replace(' favourable due to', ',').replace(',', ' favourable due to', 1)
print(df)

输出：

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

这将有助于：

df['Statement 1'] = df['Statement 1'].apply(lambda x: x.replace(' favourable due to', ',').replace(',', ' favourable due to', 1)
print(df)

输出：

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

  Name                                                   Statement 1
0    A  Value is favourable due to A, Q, U and unfavourable due to D
1    B  Value is favourable due to T, W, J and unfavourable due to O
2    C  Value is favourable due to U, D, H and unfavourable due to P
3    D  Value is favourable due to J, F, M and unfavourable due to Z

---

谢谢你的解决方案。我在我的代码中实现了上述代码，由于金额中的

“，”

，我收到了问题。并非我输入的所有句子都是相同的，所以以前没有看到过这个问题。前：

金额为1.189亿（38.5%），后：
金额为1.89亿（38.5%），后：
金额为1.379亿（12.26%），后由B 361亿（11.7%）有利驱动，有没有办法解决这个问题？感谢您的解决方案。我在我的代码中实现了上述代码，由于金额中的
“，”
，我收到了问题。并非我输入的所有句子都是相同的，所以以前没有看到过这个问题。前：
金额为1.189亿（38.5%），后：
金额为1.189亿（38.5%），后：
金额为1.379亿（12.26%），后：
金额为1.361亿（11.7%），后：
有没有办法解决这个问题？你能解释一下这个解决方案中的代码吗？你能解释一下这个解决方案中的代码吗？