Python 从列表中删除项目并更新它

我有一个游戏，玩家从列表中选择挑战：

locallist = ['Ann-Marie, the butcher (1)', 'Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

每次挑战后，我都会重新打印列表，以便他们可以选择另一个挑战，我希望它打印一个列表，不包括他们刚刚进行的人员挑战

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感谢您提供从原始列表创建集合的任何见解。然后从集合中删除拾取的项目并打印集合。

您可以从原始列表中创建集合。然后从集合中删除拾取的项目并打印集合。

您可以从原始列表中创建集合。然后从集合中删除拾取的项目并打印集合。

您可以从原始列表中创建集合。然后从集合和打印集合中删除拾取的项目。

根据用户选择的方式，您可以使用“删除”或“弹出”：

locallist = ['Ann-Marie, the butcher (1)', 'Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

pick = 'Ann-Marie, the butcher (1)'
locallist.remove('Ann-Marie, the butcher (1)')
print(locallist)

pick = 1
locallist.pop(1)
print(locallist)

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

如果要保持原始列表的完整性，请复制

locallist

：

remaining = locallist[:]
pick = 'Ann-Marie, the butcher (1)'
remaining.remove('Ann-Marie, the butcher (1)')
print(remaining)

pick = 1
remaining.pop(1)
print(remaining )

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

使用

pop

还将为您提供值，以便您可以在需要时使用：

pick = 1
challenge = remaining.pop(1)
print("You chose the following challenge: {}".format(challenge))
You chose the following challenge: Bella, the flourist (2)

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根据用户选择的方式，可以使用“删除”或“弹出”：

locallist = ['Ann-Marie, the butcher (1)', 'Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

pick = 'Ann-Marie, the butcher (1)'
locallist.remove('Ann-Marie, the butcher (1)')
print(locallist)

pick = 1
locallist.pop(1)
print(locallist)

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

如果要保持原始列表的完整性，请复制

locallist

：

remaining = locallist[:]
pick = 'Ann-Marie, the butcher (1)'
remaining.remove('Ann-Marie, the butcher (1)')
print(remaining)

pick = 1
remaining.pop(1)
print(remaining )

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

使用

pop

还将为您提供值，以便您可以在需要时使用：

pick = 1
challenge = remaining.pop(1)
print("You chose the following challenge: {}".format(challenge))
You chose the following challenge: Bella, the flourist (2)

---

根据用户选择的方式，可以使用“删除”或“弹出”：

locallist = ['Ann-Marie, the butcher (1)', 'Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

pick = 'Ann-Marie, the butcher (1)'
locallist.remove('Ann-Marie, the butcher (1)')
print(locallist)

pick = 1
locallist.pop(1)
print(locallist)

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

如果要保持原始列表的完整性，请复制

locallist

：

remaining = locallist[:]
pick = 'Ann-Marie, the butcher (1)'
remaining.remove('Ann-Marie, the butcher (1)')
print(remaining)

pick = 1
remaining.pop(1)
print(remaining )

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

使用

pop

还将为您提供值，以便您可以在需要时使用：

pick = 1
challenge = remaining.pop(1)
print("You chose the following challenge: {}".format(challenge))
You chose the following challenge: Bella, the flourist (2)

---

根据用户选择的方式，可以使用“删除”或“弹出”：

locallist = ['Ann-Marie, the butcher (1)', 'Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

pick = 'Ann-Marie, the butcher (1)'
locallist.remove('Ann-Marie, the butcher (1)')
print(locallist)

pick = 1
locallist.pop(1)
print(locallist)

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

如果要保持原始列表的完整性，请复制

locallist

：

remaining = locallist[:]
pick = 'Ann-Marie, the butcher (1)'
remaining.remove('Ann-Marie, the butcher (1)')
print(remaining)

pick = 1
remaining.pop(1)
print(remaining )

['Bella, the flourist (2)', 'Caitlyn, the painter(3)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']
['Bella, the flourist (2)', 'Daniel, the scientist (4)', 'Lauren, the Zookeeper (5)']

使用

pop

还将为您提供值，以便您可以在需要时使用：

pick = 1
challenge = remaining.pop(1)
print("You chose the following challenge: {}".format(challenge))
You chose the following challenge: Bella, the flourist (2)

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用户输入什么？？整数？？是要从列表中删除某个项目，还是要保持列表不变，但打印时不使用指定的元素？用户输入是整数用户输入的是什么？？整数？？是要从列表中删除某个项目，还是要保持列表不变，但打印时不使用指定的元素？用户输入是整数用户输入的是什么？？整数？？是要从列表中删除某个项目，还是要保持列表不变，但打印时不使用指定的元素？用户输入是整数用户输入的是什么？？整数？？是要从列表中删除某个项目，还是保持列表不变，但打印时保留指定的元素？用户输入无效integers@Hackaholic，这两方面我都讲过了scenarios@hennessyd不worries@Hackaholic，这两方面我都讲过了scenarios@hennessyd不worries@Hackaholic，这两方面我都讲过了scenarios@hennessyd,不worries@Hackaholic，这两方面我都讲过了scenarios@hennessyd，不用担心