Python 选择子项作为树中的当前项
考虑以下完全扩展的玩具树,其中我将Python 选择子项作为树中的当前项,python,python-3.x,pyqt,pyqt5,Python,Python 3.x,Pyqt,Pyqt5,考虑以下完全扩展的玩具树,其中我将Alpha作为当前根: from PyQt5 import QtWidgets class MainWindow(QtWidgets.QMainWindow): def __init__(self): super(MainWindow, self).__init__() self.setMinimumHeight(300) self.setMinimumWidth(100) my_tr
Alpha
作为当前根:
from PyQt5 import QtWidgets
class MainWindow(QtWidgets.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
self.setMinimumHeight(300)
self.setMinimumWidth(100)
my_tree = QtWidgets.QTreeWidget(self)
my_tree.resize(100, 300)
alpha = QtWidgets.QTreeWidgetItem(my_tree, ['Alpha'])
beta = QtWidgets.QTreeWidgetItem(my_tree, ['Beta'])
alpha.addChild(QtWidgets.QTreeWidgetItem(['one']))
alpha.addChild(QtWidgets.QTreeWidgetItem(['two']))
beta.addChild(QtWidgets.QTreeWidgetItem(['first']))
beta.addChild(QtWidgets.QTreeWidgetItem(['second']))
my_tree.expandAll()
my_tree.setCurrentItem(my_tree.topLevelItem(0))
self.show()
app = QtWidgets.QApplication([])
window = MainWindow()
app.exec_()
如何使Alpha
(即one
)的第一个子项成为当前和选定的项目,同时只展开Beta
,而不是两个根?您可以使用setExpanded()展开或折叠项目:
alpha.setExpanded(False)
我刚刚注意到您的代码中有my_tree.expandAll()
。如果要折叠其中一个项目,请在.expandAll()之后使用item.setExpanded(False)
要将alpha中的第一个子项设置为选定项,请使用:
alpha.child(0).setSelected(True)
print(alpha.child(0).isSelected()) #verify it's selected
在代码中放置它们的位置:
.
.
beta.addChild(QtWidgets.QTreeWidgetItem(['first']))
beta.addChild(QtWidgets.QTreeWidgetItem(['second']))
my_tree.expandAll()
my_tree.setCurrentItem(my_tree.topLevelItem(0))
alpha.setExpanded(False)
alpha.child(0).setSelected(True)
print(alpha.child(0).isSelected()) # verify it's selected
self.show()
要在选择更改时运行函数,请尝试以下代码,它将打印所选项目或子项的文本(将其置于self.show之前):
my_tree.itemSelectionChanged.connect(lambda: selected_item())
def selected_item():
getSelected = my_tree.selectedItems()
if getSelected:
baseNode = getSelected[0]
getChildNode = baseNode.text(0)
print(getChildNode)