Python 根据值是否已存在于列表中追加

我有一张空名单。我想在其中添加字符串，但如果它们已经存在，请稍微更改它们。大概是这样的：

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

姓名：约翰，大卫，约翰，路易斯，肖恩，约翰，大卫

附加后的列表：约翰，大卫，约翰2，路易斯，肖恩，约翰3，大卫2

我是这样想的：

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

然而，这给了我们：约翰，大卫，约翰2，路易斯，肖恩，约翰3，大卫4，最后一个大卫应该是大卫2。我找不到根据特定名称出现的次数来更改itter的方法。 提前感谢您的帮助。

您可以有这样一个：

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

你可以有一个这样的

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

对于每个不同的名称，您需要一个单独的itter，以跟踪单独的计数。一种方法是使用集合。计数器：

输出：

['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']
>>> 

对于每个不同的名称，您需要一个单独的itter，以跟踪单独的计数。一种方法是使用集合。计数器：

输出：

['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']
>>> 

---

您还可以对子列表从开始到当前值使用count方法，如下所示：

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

---

您还可以对子列表从开始到当前值使用count方法，如下所示：

            names_list = []
            names = [ 'John' , 'David', 'John', 'Luis, 'Sean', 'John', 'David']
            itter = 1
            for _ in names:
                if any(names[_] in s for s in name_list):
                    button_list.append(names[_] + f'_{itter+1}')
                    itter+=1
                else:
                    button_list.append(names[_])

In [3215]: def rename_duplicates(old):
      ...:     seen = {}
      ...:     for x in old:
      ...:         if x in seen:
      ...:             seen[x] += 1
      ...:             yield "%s_%d" % (x, seen[x])
      ...:         else:
      ...:             seen[x] = 1
      ...:             yield x
      ...: 

In [3216]: list(rename_duplicates(names))
Out[3216]: ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']

names = [ 'John' , 'David', 'John', 'Luis', 'Sean', 'John', 'David']
names_list = []
for i in range(len(names)):
    name = names[i]
    count = names[:i].count(name)  # count the names in the sublist
    if count:
        names_list.append(f"{name}_{count+1}")
    else:
        names_list.append(name)

print(names_list)
#  ['John', 'David', 'John_2', 'Luis', 'Sean', 'John_3', 'David_2']