重新格式化Python';将向量列表结果转换为单个逗号分隔的结果
如何将向量数组(Python)的结果重新格式化为单个逗号分隔的结果 我有以下结果:重新格式化Python';将向量列表结果转换为单个逗号分隔的结果,python,arrays,regex,Python,Arrays,Regex,如何将向量数组(Python)的结果重新格式化为单个逗号分隔的结果 我有以下结果: [ ['44231#0:', '2016/10/11', '11:19:23', '11:19:23', '1', '11:19:24', '11:19:24' , '0'] ['44231#0:', '2016/10/11', '12:20:39', '12:20:58', '12:20:59', '12:20:59', '0'] ] 我需要像这样的东西: 44231#0:, 2016/10/11,
[ ['44231#0:', '2016/10/11', '11:19:23', '11:19:23', '1', '11:19:24', '11:19:24'
, '0']
['44231#0:', '2016/10/11', '12:20:39', '12:20:58', '12:20:59', '12:20:59', '0']
]
我需要像这样的东西:
44231#0:, 2016/10/11, 11:19:23, 11:19:23, 1, 11:19:24, 11:19:24
44231#0:, 2016/10/11, 12:20:39, 12:20:58, 12:20:59, 12:20:59, 0
有人吗
提前谢谢你 简单的方法是使用两个for循环
for d in data:
s = ''
for l in d:
s += l + ', '
print(s[:-2])
您正在尝试创建字符串列表吗?做:
[', '.join(sublist) for sublist in data]