Python 在字符串中查找数字,添加1并替换
我需要编写一个代码,其中一个字符串包含一个数字,然后这个数字递增1,然后在初始字符串输入中打印出来 应该是这样的Python 在字符串中查找数字,添加1并替换,python,string,digit,Python,String,Digit,我需要编写一个代码,其中一个字符串包含一个数字,然后这个数字递增1,然后在初始字符串输入中打印出来 应该是这样的 >>>addNumber('I slept 3 hours') what number would you like to increment? 3 I slept 4 hours >>>addNumber('I have 366 friends on facebook') what number would you like to increme
>>>addNumber('I slept 3 hours')
what number would you like to increment? 3
I slept 4 hours
>>>addNumber('I have 366 friends on facebook')
what number would you like to increment? 6
I have 377 friends on facebook
到目前为止,我有这个,但我知道这是错误的,老实说,我不知道如何做到这一点
def incrementNumbers(statement):
number1=(int(input('What number would you like to increment?')))
number2 = number1 +1
i=[]
for numbers in statement:
if numbers.isdigit():
i.append(numbers)
statement.replace(numbers,number2)
你可以在这里用
另一个例子
>>> s = 'I slept 3 hours'
>>> i = raw_input('what number would you like to increment?')
what number would you like to increment?3
>>> re.sub('({})'.format(i),addone,s)
'I slept 4 hours'
你可以像这样定义你的函数
def addNumber(s):
def addone(obj):
val = int(obj.group(1))
return str(val+1)
i = raw_input('what number would you like to increment?')
return(re.sub('({})'.format(i),addone,s))
但是,我建议您有一个验证功能
i = raw_input('what number would you like to increment?')
if 0<int(i)<9:
return(re.sub('({})'.format(i),addone,s))
else:
return "Number out of range"
i=raw\u输入('您希望增加多少?'))
如果0根据您的要求,数值必须介于0和8之间,则可以使用
代码中可能存在的错误是:
您试图直接用字符串中的int
类型数据替换
此外,无论您指定要修改什么,仅检查numbers.isdigit()
将修改所有数字
为使代码正常运行,可能对代码进行的更正:
def incrementNumbers(statement):
number1 = int(input('What number would you like to increment?'))
number2 = number1 +1
i=[]
for numbers in statement:
if numbers.isdigit() and int(numbers) == number1:
i.append(numbers)
statement.replace(numbers,str(number2))
您还可以将incrementNumbers(语句)
函数更改为:
def incrementNumbers(statement):
number1 = input('What number would you like to increment?')
number2 = str(int(number1)+1)
statement = statement.replace(number1,number2)
return statement
我认为这比在循环中使用要好。如果他们想在399
中增加9
该怎么办?我不认为它会被测试为9,它只显示一个正数字。所以它必须是0-89,既有正的也有单的。是的,但这是一个非常简单的类,所以我假设我们只需要从0到8的数字
def incrementNumbers(statement):
number1 = int(input('What number would you like to increment?'))
number2 = number1 +1
i=[]
for numbers in statement:
if numbers.isdigit() and int(numbers) == number1:
i.append(numbers)
statement.replace(numbers,str(number2))
def incrementNumbers(statement):
number1 = input('What number would you like to increment?')
number2 = str(int(number1)+1)
statement = statement.replace(number1,number2)
return statement