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Python 随机更改numpy数组值_Python_Numpy - Fatal编程技术网

Python 随机更改numpy数组值

Python 随机更改numpy数组值,python,numpy,Python,Numpy,我有一个数组数据 import numpy as np data = np.array([[1,0,4,1,1,2,0], [1,0,0,4,0,1,0], [4,0,4,3,2,1,0], [4,0,1,1,2,1,1]]) print(data) 如果一些非零元素(1,2,3,4)的计数超过5,我想随机抽取并保留5个位置,并将所有其他位置替换为0 uniques, counts = n

我有一个数组数据

import numpy as np

data = np.array([[1,0,4,1,1,2,0],
                 [1,0,0,4,0,1,0],
                 [4,0,4,3,2,1,0],
                 [4,0,1,1,2,1,1]])

print(data)
如果一些非零元素(1,2,3,4)的计数超过5,我想随机抽取并保留5个位置,并将所有其他位置替换为0

uniques, counts = np.unique(data, return_counts=True)
for unique, count in zip(uniques, counts):
    print (unique, count)

    if count > 5:       
       
       ids = np.random.choice(range(count), 5, replace=False)

我该怎么做?

当计数超过5时,只保留5个位置或唯一非零元素的所有位置?如果计数超过5,则只保留5个位置。这行的替代方法是什么,
data[tuple(I[id]表示np中的I.where(data==unique))]=0
?我无法理解该行可能这行更容易理解,
x,y=np.where(data==unique)
对于ID中的I:data[x[I],y[I]=0
uniques, counts = np.unique(data, return_counts=True)
for unique, count in zip(uniques, counts):
    print (unique, count)
    if unique != 0 and count > 5:
       ids = np.random.choice(count, count-5, replace=False)
       data[tuple(i[ids] for i in np.where(data == unique))] = 0