Python 获取拆分后的子字符串的值

我有一个json文件，看起来像这样：

{
    "model": "Sequential",
    "layers": [
        {
            "L1": "Conv2D(filters = 64, kernel_size=(2,2), strides=(2,2), padding='same', data_format='channels_last', activation='relu', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.), input_shape=(224,224,3))",
            "L2": "MaxPooling2D(pool_size=(2,2), strides=(2,2), padding='same', data_format='channels_last')",
            "L3": "Conv2D(filters = 64, kernel_size=(2,2), strides=(2,2), padding='same', data_format='channels_last', activation='relu', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L4": "MaxPooling2D(pool_size=(2,2), strides=(2,2), padding='same', data_format='channels_last')",
            "L5": "Conv2D(filters = 64, kernel_size=(2,2), strides=(2,2), padding='same', data_format='channels_last', activation='relu', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L6": "Conv2D(filters = 64, kernel_size=(2,2), strides=(2,2), padding='same', data_format='channels_last', activation='relu', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L7": "Conv2D(filters = 64, kernel_size=(2,2), strides=(2,2), padding='same', data_format='channels_last', activation='relu', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L8": "MaxPooling2D(pool_size=(2,2), strides=(2,2), padding='same', data_format='channels_last')",
            "L9": "Flatten()",
            "L10": "Dense(4096, activation='softmax', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L11": "Dropout(0.4)",
            "L12": "Dense(2048, activation='softmax', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L13": "Dropout(0.4)",
            "L14": "Dense(1000, activation='softmax', use_bias=True, kernel_initializer='zeros', bias_initializer='zeros', kernel_regularizer=regularizers.l1(0.), bias_regularizer=regularizers.l1(0.), activity_regularizer=regularizers.l1(0.), kernel_constraint=max_norm(2.), bias_constraint=max_norm(2.))",
            "L15": "Dropout(0.4)"
        }
    ]
}

我想获得关于json文件中存在哪一层的信息。例如，Conv2D、MaxPooling2D、flatte（）等

另外，我想知道字符串的值，比如过滤器、内核大小、步幅、激活等

我尝试通过以下操作获取图层名称：

with open('model.json','r') as fb:
    con = json.load(fb)
con['layers'][0]['L1'].split('(', 1)[0].rstrip()

c = con['layers'][0]['L1'].split('(', 1)[1].rstrip()
c.split(',')
['filters = 8', ' kernel_size=(3', '3)', ' strides=(1', ' 1)', " padding='valid'", " data_format='channels_last'", " activation='relu'", ' use_bias=True', " kernel_initializer='zeros'", " bias_initializer='zeros'", ' kernel_regularizer=regularizers.l1(0.)', ' bias_regularizer=regularizers.l1(0.)', ' activity_regularizer=regularizers.l2(0.)', ' kernel_constraint=max_norm(2.)', ' bias_constraint=max_norm(2.)', ' input_shape=(28', '28', '1))']

输出为

'Conv2d'

。类似地，我得到了其他图层名称

我需要的帮助是获取过滤器的值（如L1中的64）

我试着这样做：

with open('model.json','r') as fb:
    con = json.load(fb)
con['layers'][0]['L1'].split('(', 1)[0].rstrip()

c = con['layers'][0]['L1'].split('(', 1)[1].rstrip()
c.split(',')
['filters = 8', ' kernel_size=(3', '3)', ' strides=(1', ' 1)', " padding='valid'", " data_format='channels_last'", " activation='relu'", ' use_bias=True', " kernel_initializer='zeros'", " bias_initializer='zeros'", ' kernel_regularizer=regularizers.l1(0.)', ' bias_regularizer=regularizers.l1(0.)', ' activity_regularizer=regularizers.l2(0.)', ' kernel_constraint=max_norm(2.)', ' bias_constraint=max_norm(2.)', ' input_shape=(28', '28', '1))']

但我仍然没有得到价值

---

有人知道如何获取这些信息吗？

更新：使用regex可以提取关键字参数。然后在“=”上拆分以查找每个层的每个关键字参数的值

import json
import re

with open('model.json','r') as fb:
  con = json.load(fb)

for layer_key in con['layers'][0]:
  print("Layer: {}".format(layer_key))
  layer = con['layers'][0][layer_key]
  layers_kwargs = re.sub('^(.*?)\(', '', layer)[:-1]
  if not layers_kwargs:
    print('No kwargs')
    continue
  for kwarg in layers_kwargs.split(', '):
    kwarg = [i.strip() for i in kwarg.split('=')]
    if len(kwarg) != 2:
      print('No key', kwarg)
      continue
    k = kwarg[0]
    v = kwarg[1]
    print(k,v)

---

使用正则表达式-供进一步参考

import re

string_lst = ['filters','kernel_size','stride','activation']
my_dict = {}
for key,value in con['layers'][0].items():
    my_dict[key] = {}
    layer_names = value.split('(')[0].rstrip()
    my_dict[key][layer_names] = {}
    for i in string_lst:
        match = re.search(i+'(.+?), ', value)
        if match:
            filters = match.group(1).split("=")[1].strip()
            my_dict[key][layer_names][i] = filters

    if len(my_dict[key][layer_names]) <= 0:
        del my_dict[key]

print(my_dict)

JSON包含重复的层名称，如果需要唯一的记录，请替换所有行

my_dict[key][layer_names]

至

my_dict[layer_names]

---

然后删除这个

my_dict[key]={}

行

我将分两步完成。首先为外部筛选器名称和内容创建一个正则表达式

re.compile(r"^\s*([^(]*)\s*\((.*)\)\s*$")

这有两个组，

名称

，以及括号中的内容（…）

然后生成一个正则表达式，在不在括号内的逗号上拆分。你可以看到一个深入的问题

演示：

印刷品：

Conv2D
['filters = 64', 'kernel_size=(2,2)', "padding='same"]

---

如果字符串不包含筛选器，则该字符串应返回0。当我搜索“激活”时，该字符串不返回字符串。它正在给IndexError:list索引超出范围。例如，在L1中，它应该返回'relu'。是的，它工作了，但现在在内核大小和步长等方面，整个元组都没有返回（例如（3,3））@AshutoshMishra更新了我的答案，现在试试。

Conv2D
['filters = 64', 'kernel_size=(2,2)', "padding='same"]