python数据字典输出
我道歉了,因为我对python很陌生。我迭代了几个名称,它们都得到了相同的字典键和值。我怎样才能只打印一次密钥,并根据迭代将值添加到csvpython数据字典输出,python,csv,import,data-dictionary,Python,Csv,Import,Data Dictionary,我道歉了,因为我对python很陌生。我迭代了几个名称,它们都得到了相同的字典键和值。我怎样才能只打印一次密钥,并根据迭代将值添加到csv for name in namelist: print >> out,','.join(data.keys()) print >> out,','.join(data.values()) fundamental_out.close() 输出如下所示 >>'key1,k
for name in namelist:
print >> out,','.join(data.keys())
print >> out,','.join(data.values())
fundamental_out.close()
输出如下所示
>>'key1,key2,key3'
>>'value1,value2,value3'
>>'key1,key2,key3'
>>'value1,value2,value3'
假设key3是名称,key1和Key2是数字
我如何获得这样的输出
>>'key1,key2,key3'
>>'value1,value2,value3'
>>'value1,value2,value3'
还有没有一种方法可以按顺序对数据字典进行排序,以便键3(即名称将是第一列)
谢谢 您可以使用对字典键进行排序:
import re
def natural_sort(l):
#https://stackoverflow.com/a/4836734/846892
convert = lambda text: int(text) if text.isdigit() else text.lower()
alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ]
return sorted(l, key = alphanum_key)
sorted_keys = ['key3'] + natural_sort(data.viewkeys() - {'key3'})
print >> out, ','.join(keys)
for name in namelist:
print >> out, ','.join(str(data[k]) for k in keys)
谢谢但是,如何用键打印出第一行,用值向前打印出第二行?迭代出一个名称列表,并确保值与具有相应“键变量”的名称相对应?非常感谢!它有助于分类。但仍然在每次迭代中打印出密钥。有没有一种方法可以只打印一次键,并且每次迭代时值都会一直打印?
import re
def natural_sort(l):
#https://stackoverflow.com/a/4836734/846892
convert = lambda text: int(text) if text.isdigit() else text.lower()
alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ]
return sorted(l, key = alphanum_key)
sorted_keys = ['key3'] + natural_sort(data.viewkeys() - {'key3'})
print >> out, ','.join(keys)
for name in namelist:
print >> out, ','.join(str(data[k]) for k in keys)
from itertools import chain
def arrange(l):
return list(chain([l[-1]], l[:-1]))
print ','.join(arrange(map(lambda x: str(x), namelist.keys())))
print ','.join(arrange(map(lambda x: str(x), namelist.values())))