Python 如何使用Numpy数组查找给定值的x和y坐标

要使用2D numpy数组制作棋盘游戏，用户需要输入一个数字，我需要在单独的变量中返回该数字的X&Y值

这就是我设置阵列的方式

board = np.array(["01","02","03","04","05","06","07","08",
                      "09","10","11","12","13","14","15","16",
                      "17","18","19","20","21","22","23","24",
                      "25","26","  ","@@","29","30","31","32",
                      "33","34","35","@@","  ","38","39","40",
                      "41","42","43","44","45","46","47","48",
                      "49","50","51","52","53","54","55","56",
                      "57","58","59","60","61","62","63","64"])
board = board.reshape(8,8)

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这可以通过多种方式实现。其中之一可以是：

value = input("Enter the board value")  # This allows the user to enter the value

found = np.squeeze(np.where(value == board))  # This numpy function finds where the array is equal to the board value

if found.size > 0:  # checks if the found value is not empty
    print('The value is present in the board at {}, {}'.format(found[0], found[1]))
else:
    print('Enter a valid input')

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谢谢，明白了working@WilliamKavanagh很高兴知道。然而，这将导致一个不明确的结果，即两次出现这种情况。如果您希望将其作为特殊用途的case，可以将其添加为elseif（在python:elif中）case。你想让我来处理吗？或者你想把它作为一个学习过程，自己去弄清楚。我建议晚一点；）由于阵列的性质，我知道它不会抛出双阵列，但感谢您的提议。我把它作为一个学习的经验，因为我觉得我将要使用numpy alotin这段代码的东西将不得不去非常错误的双重发生，但感谢你的提议。我想我现在会把它当作一种学习经验。我不想依赖这个网站