这段代码[Python]有什么问题？

各位好,

我是一个初级程序员，我遇到了一个我无法解决的问题。当我在Python3 shell中运行我的程序时，它会显示无效语法，并在第1行中标记“：”，这意味着那里有问题。对于所有其他if/else/ifelse语句，它并没有说：是无效语法。如果我删除“：”，它将choice1（）标记为红色，表示语法不正确，而缩进正好有4个空格

我真的不知道代码出了什么问题，谢谢所有帮助我的人

这是一个屏幕截图：（缩进等）

关闭从用户处获取输入的行上的括号

删除

elif option==“4”

删除break语句，那里没有循环

代码：

---

缩进你函数下的所有代码行

def gamemenu（）：

直到

print 5 exit

你的代码就是这样的吗？你有缺少的参数，没有循环的中断和多个缩进错误。首先，你不是说“第1行”，这是一个注释。您的意思是“if option==”1:“行。这里的错误很明显，在上面的一行，你没有关闭ParenthSis。另外，你的很多代码没有正确缩进，这会导致它失败——这是Python，缩进很重要。我已经做了，但它没有出现在这里的代码中，这里缺少一个截图）呃，我太笨了，谢谢，哈哈

# For updating the version!
version = "0.1"

# For game start!
from choice1 import choice1
# insert import functions from checkpoints choices here!

def gamemenu():
print("Welcome to the RTG!")
# Starts the game
print("1. START!")
# Goes to an earlier checkpoint
print("2. CHECKPOINTS!")
# Views the "about' page
print("3. ABOUT")
# Shows my website address!
print("4. INFO ABOUT CREATOR")
# Exits the game
print("5. EXIT")

# The user input!
option = input("Make your choice, buddy! "

if option == "1":
   choice1()
# elif option == "2":
# Not added yet
elif option == "3":
   print("Random Text RPG, version %s" % version)
   print("This is just a random game made by me for fun")
   print("Please dont't take offence :(")
elif option == "4":
   print("Made by Lightning Bolt."))
elif option == "5":
   break
else:
   print("ERROR: invalid option")
   menu()

menu()

# For updating the version!
version = "0.1"

# For game start!
from choice1 import choice1
# insert import functions from checkpoints choices here!

def gamemenu():
    print("Welcome to the RTG!")
    # Starts the game
    print("1. START!")
    # Goes to an earlier checkpoint
    print("2. CHECKPOINTS!")
    # Views the "about' page
    print("3. ABOUT")
    # Shows my website address!
    print("4. INFO ABOUT CREATOR")
    # Exits the game
    print("5. EXIT")

    # The user input!
    option = input("Make your choice, buddy! ") #you missed a closing parenthesis here :D

    if option == "1":
        choice1()
    # elif option == "2":
    # Not added yet
    elif option == "3":
       print("Random Text RPG, version %s" % version)
       print("This is just a random game made by me for fun")
       print("Please dont't take offence :(")
    elif option == "4":
       print("Made by Lightning Bolt.") # there was an extra paren here
    elif option == "5":
       pass #as @Padraic mentioned, there should be no break statement
    else:
       print("ERROR: invalid option")
       menu()

menu()