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Python 属性错误:';列表';对象没有属性';到excel';附加DF'时;列出,并将这些DF';s使用openpyxl保存到聚合文件_Python_Pandas_Openpyxl - Fatal编程技术网

Python 属性错误:';列表';对象没有属性';到excel';附加DF'时;列出,并将这些DF';s使用openpyxl保存到聚合文件

Python 属性错误:';列表';对象没有属性';到excel';附加DF'时;列出,并将这些DF';s使用openpyxl保存到聚合文件,python,pandas,openpyxl,Python,Pandas,Openpyxl,当我想将最终数据框保存到excel文件时,出现错误: for filename in path.glob('**/*.xlsx'): [...] [... omitted code, will share, if interest exists] [...] print('Processing : ' + str(filename)) try: data = pd.read_excel(filename, sheet_name='Main Sheet', head

当我想将最终数据框保存到excel文件时,出现错误:

for filename in path.glob('**/*.xlsx'):
[...]
[... omitted code, will share, if interest exists]
[...]
    print('Processing : ' + str(filename))
    try:
        data = pd.read_excel(filename, sheet_name='Main Sheet', header=None)
        new_row = pd.DataFrame([[str(filename), str(now)]],
                               index=[0])
        # simply concatenate both dataframes
        data = pd.concat([new_row, data]).reset_index(drop=True, inplace=True)

        appended_data.append(data)
        appended_data = pd.concat(appended_data, sort=False, ignore_index=True)
    except Exception as e:
        print(e)
        print('Couldn\'t process ' + str(filename) + ' ! ')
    copy('C:\\Users\\**YOU**\\' + str(filename), (os.path.expanduser(
        '~/') + '\\**CLOUD'))
    os.remove('C:\\Users\\**YOU**\\' + str(filename))

except Exception as e:
    print('Error! Error!: ' + str(e) + str(e.args))
循环后:

appended_data.to_excel('appended.xlsx')
book = load_workbook('appended2.xlsx')
writer = pd.ExcelWriter('appended2.xlsx', engine='openpyxl')
writer.book = book
writer.sheets = {ws.title: ws for ws in book.worksheets}
startrow = writer.sheets['Sheet1'].max_row
appended_data.to_excel(writer, startrow=startrow, index=False, header=False)
writer.save()
“AttributeError:“list”对象没有“to_excel”属性 发生在最后一排的第二排。 我很困惑,因为代码在我对循环进行一些“改进”之前就已经运行了。。 如何将列表转换为数据帧? 当我尝试一个简单的 df=pd.DataFrame(附加数据) 我得到一个“所有传递的对象都没有”


一些背景信息: 数据帧如下所示:

标题

Eaten this month    Ordered Self-made   Eaten out

Pizza   20  5   7   8
Pasta   10  1   8   1
Sushi   5       0   N/A
Chinese 15  14  1   N/A
标题被删除,聚合数据的名称和日期被写入 附加数据(最终结果):


我走近了,我不得不用append而不是concat。我也在循环之后移动了操作

data = new_row.append(data, ignore_index=True)
            appended_data.append(data)
            try:
                new_append = appended_data.append(data)
            except:
                print('Could\'nt append multiple df\'s')
            try:
                appended_data = pd.concat(new_append.reset_index(drop=True), sort=False, ignore_index=True, axis=1)
            except:
                pass
            df = pd.DataFrame(appended_data)
            df.to_excel('appended.xlsx')
            book = load_workbook('appended2.xlsx')
            writer = pd.ExcelWriter('appended2.xlsx', engine='openpyxl')
            writer.book = book
            writer.sheets = {ws.title: ws for ws in book.worksheets}
            startrow = writer.sheets['Sheet1'].max_row
            df.to_excel(writer, startrow=startrow, index=False, header=False)
            writer.save()
我还有一个问题: 最终结果中的数据帧被写入一个单元格,这似乎很奇怪。
但是从这里我想,索引可能有问题…

看看附加的数据。附加(数据),我假设附加的数据是一个列表,列表没有一个到excel的
方法你打算对附加数据中的数据执行
吗:…
?其思想是“附加数据=pd.concat(附加数据,排序=False,忽略索引=True)”在不需要另一个循环的情况下附加数据帧
data = new_row.append(data, ignore_index=True)
            appended_data.append(data)
            try:
                new_append = appended_data.append(data)
            except:
                print('Could\'nt append multiple df\'s')
            try:
                appended_data = pd.concat(new_append.reset_index(drop=True), sort=False, ignore_index=True, axis=1)
            except:
                pass
            df = pd.DataFrame(appended_data)
            df.to_excel('appended.xlsx')
            book = load_workbook('appended2.xlsx')
            writer = pd.ExcelWriter('appended2.xlsx', engine='openpyxl')
            writer.book = book
            writer.sheets = {ws.title: ws for ws in book.worksheets}
            startrow = writer.sheets['Sheet1'].max_row
            df.to_excel(writer, startrow=startrow, index=False, header=False)
            writer.save()