Python 为什么函数不返回值？

我不明白为什么函数在python中不返回，我的函数计算两个日期之间星期五和星期六的天数，但它不返回

这是我的密码：

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您需要为该字段赋值。例如，rec.days\u compensation=浮动天数

必须在for循环外部的函数返回的开始和结束处定义friandsat：

def get_compensation(self):
    friandsat = 0
    for rec in self:
        if rec.mission_start_date and rec.mission_end_date:
            time1 = datetime.datetime.strptime(rec.mission_start_date, "%Y-%m-%d")
            time2 = datetime.datetime.strptime(rec.mission_end_date, "%Y-%m-%d")
            week = {}
            leave_value = {}
    # Compute Number Of Friday And Saturday
            for i in range((time2 - time1).days):
                day = calendar.day_name[(time1 + datetime.timedelta(days=i+1)).weekday()]
                week[day] = week[day] + 1 if day in week else 1
            fri = week.get('Friday') if 'Friday' in week else 0  # Result Number 1 Of friday If "Start Date", "End date" --> "02/04/2019", "07/04/2019"
            sat = week.get('Saturday') if 'Saturday' in week else 0 # Same thing that Friday, Numbre 1 for Saturday
            friandsat = fri + sat # Result 2
    return friandsat

如果计算字段在默认情况下为只读，则删除readonly属性，除非给出了反转。 使字段store=True 更新代码

@api.取决于“任务开始日期”、“任务结束日期” def get_补偿自身： 对于rec in self： 如果记录任务开始日期和记录任务结束日期： time1=datetime.datetime.strptimerec.mission\u开始\u日期，%Y-%m-%d time2=datetime.datetime.strptimerec.mission\u end\u日期，%Y-%m-%d 周={} 左_值={} 计算星期五和星期六的数量 对于范围为Time2-time1.days的i： day=日历.day\u名称[time1+datetime.timedeltadays=i+1.weekday] 周[日]=周[日]+1如果周中的某一天，则为其他1 星期五 如果一周中的“星期五”，则为“星期五”；如果开始日期、结束日期->2019年4月2日、2019年4月7日，则为“星期五”的第1个结果 星期六=一周。如果一周中的“星期六”为“星期六”，则得到“星期六”，否则星期五为0，星期六为1 记录天数\补偿=周五+周六结果2

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这个函数是否返回None？您对self:to中的rec有什么期望？当您定义视图中的字段时，compute方法只是被调用。尝试“rec.days\u compensation=monandsat”，它在field@NabilTaleb这是float字段的默认值。@NabilTaleb您在视图中声明days\u补偿字段了吗？是的，我在视图中声明了字段，这在导入库中不是问题！不因为我在windows中使用odoo一体机，我真的不明白这是什么问题

@api.multi
@api.depends('mission_start_date', 'mission_end_date')
def get_compensation(self):
    for rec in self:
        if rec.mission_start_date and rec.mission_end_date:
            time1 = datetime.datetime.strptime(rec.mission_start_date, "%Y-%m-%d")
            time2 = datetime.datetime.strptime(rec.mission_end_date, "%Y-%m-%d")
            week = {}
            leave_value = {}
            # Compute Number Of Friday And Saturday
            for i in range((time2 - time1).days):
                day = calendar.day_name[(time1 + datetime.timedelta(days=i+1)).weekday()]
                week[day] = week[day] + 1 if day in week else 1                    
            fri = week.get('Friday') if 'Friday' in week else 0  # Result Number 1 Of friday If "Start Date", "End date" --> "02/04/2019", "07/04/2019"
            sat = week.get('Saturday') if 'Saturday' in week else 0 # Same thing that Friday, Numbre 1 for Saturday
            friandsat = fri + sat # Result 2
            rec.days_compensation = friandsat

def get_compensation(self):
    friandsat = 0
    for rec in self:
        if rec.mission_start_date and rec.mission_end_date:
            time1 = datetime.datetime.strptime(rec.mission_start_date, "%Y-%m-%d")
            time2 = datetime.datetime.strptime(rec.mission_end_date, "%Y-%m-%d")
            week = {}
            leave_value = {}
    # Compute Number Of Friday And Saturday
            for i in range((time2 - time1).days):
                day = calendar.day_name[(time1 + datetime.timedelta(days=i+1)).weekday()]
                week[day] = week[day] + 1 if day in week else 1
            fri = week.get('Friday') if 'Friday' in week else 0  # Result Number 1 Of friday If "Start Date", "End date" --> "02/04/2019", "07/04/2019"
            sat = week.get('Saturday') if 'Saturday' in week else 0 # Same thing that Friday, Numbre 1 for Saturday
            friandsat = fri + sat # Result 2
    return friandsat