Python 如何在PyQT中的类之间连接pyqtSignal

如何正确连接两个不同对象（类）之间的

pyqtSignal

？我指的是最佳实践

看看我为实现这个目标做了些什么：当

Pot

升高其温度时，

温度计

类会收到通知：

from PyQt4 import QtCore

class Pot(QtCore.QObject):
    temperatureRaisedSignal = QtCore.pyqtSignal()

    def __init__(self, parent=None):
        super(Pot, self).__init__(parent)
        self.temperature = 1
    def Boil(self):
        self.temperature += 1
        self.temperatureRaisedSignal.emit()
    def RegisterSignal(self, obj):
        self.temperatureRaisedSignal.connect(obj)

class Thermometer():
    def __init__(self, pot):
        self.pot = pot
        self.pot.RegisterSignal(self.temperatureWarning)
    def StartMeasure(self):
        self.pot.Boil()
    def temperatureWarning(self):
        print("Too high temperature!")

if __name__ == '__main__':
    pot = Pot()
    th = Thermometer(pot)
    th.StartMeasure()

或者有没有更简单/更好的方法

我还坚持（如果可能的话）使用“新”风格的PyQt信号

from PyQt4 import QtCore

class Pot(QtCore.QObject):

    temperatureRaisedSignal = QtCore.pyqtSignal()

    def __init__(self, parent=None):
        QtCore.QObject.__init__(self)
        self.temperature = 1

    def Boil(self):
        self.temperatureRaisedSignal.emit()
        self.temperature += 1

class Thermometer():
    def __init__(self, pot):
        self.pot = pot
        self.pot.temperatureRaisedSignal.connect(self.temperatureWarning)

    def StartMeasure(self):
        self.pot.Boil()

    def temperatureWarning(self):
        print("Too high temperature!")

if __name__ == '__main__':
    pot = Pot()
    th = Thermometer(pot)
    th.StartMeasure()

根据文档，我会这样做：