Python 如何获得最后一行

列=['LotFrontage'、'Alley'、'MasVnrType'、'MasVnrArea'、'BsmtQual'、'BsmtCond'、'BsmtExposure'、'BsmtFinType1'、'BsmtFinType2'， “电气”、“壁炉”、“GarageType”、“GarageYrBlt”， “GarageFinish”、“GarageQual”、“GarageSecond”、“PoolQC”， "篱笆",， “其他功能”]

list=[]
for i in columns:
    a=df_train[i].isnull().sum()
    list.append(a)
    print(list)

结果:

[259]
[259, 1369]
[259, 1369, 8]
[259, 1369, 8, 8]
[259, 1369, 8, 8, 37]
[259, 1369, 8, 8, 37, 37]
[259, 1369, 8, 8, 37, 37, 38]
[259, 1369, 8, 8, 37, 37, 38, 37]
[259, 1369, 8, 8, 37, 37, 38, 37, 38]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81, 81]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81, 81, 1453]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81, 81, 1453, 1179]
[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81, 81, 1453, 1179, 1406]

我得到的结果如上所示，但我只需要一个列表

[259, 1369, 8, 8, 37, 37, 38, 37, 38, 1, 690, 81, 81, 81, 81, 81, 1453, 1179, 1406]

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只需将打印从for循环中输出，它将只打印最后一行

unident printlist。可以使用if语句在col中为i写入循环来帮助查找函数的数据类型：if df_train[i]='int'：printTrue使用此循环，我必须通过了解数据类型来填充na值

list=[]
for i in columns:
    a=df_train[i].isnull().sum()
    list.append(a)
print(list)