Python 使用相同的django表单编辑/添加对象

我已经用了答案，但由于某种原因，我没有得到一个好结果

我正在尝试对编辑表单和添加表单使用相同的模板。这是我的

url.py

：

url(r'^app/student/new/$', 'edit_student', {}, 'student_new'),
url(r'^app/student/edit/(?P<id>\d+)/$', 'edit_student', {}, 'student_edit'),

def edit_student(request, id=None, template_name='student_edit_template.html'):
if id:
    t = "Edit"
    student = get_object_or_404(Student, pk=id)
    if student.teacher != request.user:
        raise HttpResponseForbidden()
else:
    t = "Add"
    student = Student(teacher=request.user)

if request.POST:
    form = StudentForm(request.POST, instance=student)
    if form.is_valid():
        form.save()

        # If the save was successful, redirect to another page
        redirect_url = reverse(student_save_success)
        return HttpResponseRedirect(redirect_url)

else:
    form = StudentForm(instance=student)

return render_to_response(template_name, {
    'form': form,
    't': t,
}, context_instance=RequestContext(request))

class StudentForm(ModelForm):
class Meta:
    model = Student
    exclude = ('teacher',)

和我的

forms.py

：

url(r'^app/student/new/$', 'edit_student', {}, 'student_new'),
url(r'^app/student/edit/(?P<id>\d+)/$', 'edit_student', {}, 'student_edit'),

def edit_student(request, id=None, template_name='student_edit_template.html'):
if id:
    t = "Edit"
    student = get_object_or_404(Student, pk=id)
    if student.teacher != request.user:
        raise HttpResponseForbidden()
else:
    t = "Add"
    student = Student(teacher=request.user)

if request.POST:
    form = StudentForm(request.POST, instance=student)
    if form.is_valid():
        form.save()

        # If the save was successful, redirect to another page
        redirect_url = reverse(student_save_success)
        return HttpResponseRedirect(redirect_url)

else:
    form = StudentForm(instance=student)

return render_to_response(template_name, {
    'form': form,
    't': t,
}, context_instance=RequestContext(request))

class StudentForm(ModelForm):
class Meta:
    model = Student
    exclude = ('teacher',)

最后是我的模板

student\u edit\u template.html

：

<h1>{{ t }} Student</h1>
<form action="/app/student/edit/{{ student.id }}" method="post"> {% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Submit" />
</form>

我可能错过了一些简单的东西，但在这一点上，我至少需要另一双眼睛

---

提前谢谢

您之所以获得404，是因为

/student/edit/

在末尾需要一个id，否则就没有路线，而且当您来自

/student/new/

时，您还没有id。为

/student/edit/

创建一个路由和视图，并将逻辑放在其中，以处理在POST上创建记录时的情况。

一件事是：该URL需要看起来像

http://192.168.1.3:5678/app/student/edit/789/

或诸如此类--您的URL中没有ID，因此是404。对——但是你可以从我发布到那个学生ID的模板中看到，它应该发布到那个URL。我应该说得更具体些——当我添加一条记录时，它是404'ing。这与尚未生成的id有关吗？是的，就是这样。我没有将

student

传递给模板，因此

id

在任何情况下都不会被填充。我必须通过

student

，然后将我的POST调用更改为尾部斜杠。这就成功了。