Python 如何在椭圆路径上放置等间距的圆？

我有一个小的（实际上是大的）任务要处理，我想知道是否有人能帮我解决这个问题。我已经寻找了好几次答案，但都没有成功

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（）如果有人需要，多亏了Kevin发布的链接，我才能够做到这一点

下面是它的工作原理

def __init__(self, master, number_of_people, node_size):
    a = 350
    b = 140
    ellipsePoints = [(a * cos(theta), b * sin(theta))
                     for theta in (pi*2 * i/number_of_people for i in range(number_of_people))]
    DisplayFrame = Canvas(root, bg="white", width=725, height=320)
    DisplayFrame.grid(row=0, columnspan=7, column=0, sticky='W', padx=5, pady=5)
    for i in range(number_of_people):
            DisplayFrame.create_oval(ellipsePoints[i][0]+355, ellipsePoints[i][1]+155,
                                     ellipsePoints[i][0]+355+node_size, ellipsePoints[i][1]+155+node_size, fill="red")

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这可能对您有所帮助：。生成点，然后将每个点用作圆心。每个圆的直径是任意两个相邻点之间的最小直线距离。谢谢您的回答！我有点困惑，因为Tkinter要求将圆定义为“封闭在矩形中”，所以我必须在每个点周围定义一个矩形。无论如何，谢谢。

def __init__(self, master, number_of_people, node_size):
    a = 350
    b = 140
    ellipsePoints = [(a * cos(theta), b * sin(theta))
                     for theta in (pi*2 * i/number_of_people for i in range(number_of_people))]
    DisplayFrame = Canvas(root, bg="white", width=725, height=320)
    DisplayFrame.grid(row=0, columnspan=7, column=0, sticky='W', padx=5, pady=5)
    for i in range(number_of_people):
            DisplayFrame.create_oval(ellipsePoints[i][0]+355, ellipsePoints[i][1]+155,
                                     ellipsePoints[i][0]+355+node_size, ellipsePoints[i][1]+155+node_size, fill="red")