Python I';我的代码有问题。它只打印手上两个值中的一个
我正在做一个纸牌游戏,我想做一个函数来打印手中纸牌的价值。但是,它只打印最后一张拾取的卡的值 我试着用一个不同的函数来计算卡片的值,这个函数与用于拾取具有相同结果的卡片的函数不同 甲板和变量:Python I';我的代码有问题。它只打印手上两个值中的一个,python,global-variables,global,Python,Global Variables,Global,我正在做一个纸牌游戏,我想做一个函数来打印手中纸牌的价值。但是,它只打印最后一张拾取的卡的值 我试着用一个不同的函数来计算卡片的值,这个函数与用于拾取具有相同结果的卡片的函数不同 甲板和变量: heartsCards = ["Ace of Hearts","Two of Hearts","Three of Hearts","Four of Hearts","Five of Hearts","Six of Hearts","Seven of Hearts","Eight of Hearts","N
heartsCards = ["Ace of Hearts","Two of Hearts","Three of Hearts","Four of Hearts","Five of Hearts","Six of Hearts","Seven of Hearts","Eight of Hearts","Nine of Hearts","Ten of Hearts","Jack of Hearts","Queen of Hearts","King of Hearts"]
diamondsCards = ["Ace of Diamonds","Two of Diamonds","Three of Diamonds","Four of Diamonds","Five of Diamonds","Six of Diamonds","Seven of Diamonds","Eight of Diamonds","Nine of Diamonds","Ten of Diamonds","Jack of Diamonds","Queen of Diamonds","King of Diamonds"]
clubsCards = ["Ace of Clubs","Two of Clubs","Three of Clubs","Four of Clubs","Five of Clubs","Six of Clubs","Seven of Clubs","Eight of Clubs","Nine of Clubs","Ten of Clubs","Jack of Clubs","Queen of Clubs","King of Clubs"]
spadesCards = ["Ace of Spades","Two of Spades","Three of Spades","Four of Spades","Five of Spades","Six of Spades","Seven of Spades","Eight of Spades","Nine of Spades","Ten of Spades","Jack of Spades","Queen of Spades","King of Spades"]
yourCards = []
cardValue = 0
拾取功能:
def pickUp():
randomNum = random.randint(1,4)
global cardValue
if randomNum == 1:
temp = random.choice(heartsCards)
if heartsCards.index(temp) < 10:
cardValue =+ heartsCards.index(temp) + 1
else:
cardValue =+ 10
yourCards.append(temp)
heartsCards.remove(temp)
if randomNum == 2:
temp = random.choice(diamondsCards)
if diamondsCards.index(temp) < 10:
cardValue =+ diamondsCards.index(temp) + 1
else:
cardValue =+ 10
yourCards.append(temp)
diamondsCards.remove(temp)
if randomNum == 3:
temp = random.choice(clubsCards)
if clubsCards.index(temp) <10:
cardValue =+ clubsCards.index(temp) + 1
else:
cardValue =+ 10
yourCards.append(temp)
clubsCards.remove(temp)
if randomNum == 4:
temp = random.choice(spadesCards)
if spadesCards.index(temp) < 10:
cardValue =+ spadesCards.index(temp) + 1
else:
cardValue =+ 10
yourCards.append(temp)
spadesCards.remove(temp)
def cardCount():
temp = 0
global cardValue
for card in yourCards:
if card.count("Ace"):
temp =+ 1
if temp == 0:
print ("The value of your cards is",str(cardValue) + ".")
if temp == 1:
print ("The value of your cards is",cardValue,"or",str(cardValue + 10) , ".")
if temp == 2:
print ("The value of your cards is",cardValue,"or",str(cardValue + 10),"or",str(cardValue + 10) , ".")
使用一副两张卡调用cardCount()后,打印的唯一值是后一张卡的值。e、 g.对于2个红桃和8个黑桃的组合,函数将值打印为8。我认为问题的发生是因为cardValue没有增加 在您的代码中有
cardValue=+heartsCards.index(temp)+1
或cardValue=+10
,这是不正确的
将所有位置更改为cardValue+=任意值
这是变量的增量:
a = 10
a += 100
print(a) #=> 110
这将指定以下值:
a =+ 1
print(a) #=> 1
# same as a = +1
如果您定义
val=[]
,然后在每个If语句的末尾添加val.append(cardValue)
,您将得到一个包含当前值的列表。我想你的问题是为什么cardValue
没有增加,不是吗?@iGian我不明白?我明白你面临的问题了吗?我的意思是,cardValue
不是递增的。对吗?我不明白它是如何工作的,但它确实如此。谢谢:)我补充了一个解释。