Python django 2 re_路径表达式传递电子邮件验证令牌

我一直坚持在Django2URL中使用正则表达式。 一切似乎都是正确的，但是我得到了

404

错误

实际路径：

http://localhost:8000/user/activate/b'MjQ'/4zb-89a933fe70e0d12de725/

错误：

Using the URLconf defined in ec2django.urls, Django tried these URL        patterns, in this order:

user/
^user/activate/(?P<uidb64>[0-9A-Za-z_\-]+)/(?P<token>[0-9A-Za-z]{1,13}-[0-9A-Za-z]{1,20})/$ [name='activate']
health/
^static\/(?P<path>.*)$

The current path, user/activate/b'MjQ'/4zb-89a933fe70e0d12de725/, didn't match any of these.

核查：

try:
    uid = force_text(urlsafe_base64_decode(uidb64))
    user = MyUser.objects.get(pk=uid)
except(TypeError, ValueError, OverflowError, MyUser.DoesNotExist):
    user = None
if user is not None and default_token_generator.check_token(user, token):
    user.is_active = True
    user.save()

---

url或令牌格式有问题吗？感谢您的帮助。

您的url包含单引号（

b'MjQ'

）作为第一个模式的参数，它与regex

[0-9A-Za-z\-]

不匹配。那么uid应该如何传输呢？我发现的大多数样本都以这种方式传递

uid

，模式如下所示。在本例中，它是python代码，它属于python脚本，而不是模板中呈现的url。如何在模板中对URL进行编码？回答：

            from django.utils.encoding import force_bytes
            from django.utils.http import urlsafe_base64_encode
            from django.template.loader import render_to_string
            from django.contrib.auth.tokens import default_token_generator

            message = render_to_string('email_account_activate.html', {
                'uid': urlsafe_base64_encode(force_bytes(user.pk)),
                'token': default_token_generator.make_token(user),
            })

try:
    uid = force_text(urlsafe_base64_decode(uidb64))
    user = MyUser.objects.get(pk=uid)
except(TypeError, ValueError, OverflowError, MyUser.DoesNotExist):
    user = None
if user is not None and default_token_generator.check_token(user, token):
    user.is_active = True
    user.save()