Python 使用for循环创建嵌套字典
我有一个csv文件,正在尝试创建一个嵌套字典,如下所示:Python 使用for循环创建嵌套字典,python,python-3.x,csv,dictionary,Python,Python 3.x,Csv,Dictionary,我有一个csv文件,正在尝试创建一个嵌套字典,如下所示: contacts = {"Tom": {"name": "Tom Techie", "phone": "123 123546", "email": "tom@tom.fi", "skype": "skypenick"}, "Mike": {"name": "Mike Mechanic",
contacts = {"Tom": {"name": "Tom Techie",
"phone": "123 123546",
"email": "tom@tom.fi",
"skype": "skypenick"},
"Mike": {"name": "Mike Mechanic",
"phone": "000 123546",
"email": "mike@mike.fi",
"skype": "-Mike-M-"}}
def line_to_dict(x, d):
x = x.split(";")
d[x[0]] = {
"name": x[2],
"phone": x[3],
"email": x[1],
"skype": x[4][:-1] # Slice off trailing newline
}
with open("df.csv", "r") as file:
d = {}
for x in file:
line_to_dict(x, d)
d.pop("")
等
这就是我写的:
file = open("csv","r")
d = {}
for i in file:
f = i.strip()
x = f.split(";")
if x[4] != "":
d.update({x[0] : {"name":x[1],
"phone":x[2],
"email":x[3],
"skype":x[4]}})
else:
d.update ({x[0] : {"name": x[1],
"phone": x[2],
"email": x[3]}})
然而,它将dict作为一个普通的字典打印,当更新应该像上面所说的那样时,它将更新作为键
编辑:
csv的第一行:
key;name;phone;email;skype
Tom;Tom Techie;123 123546;tom@tom.fi;skypenick
Mike;Mike Mechanic;000 123456;mike@mike.fi;-Mike-M-
Archie;Archie Architect;050 987654;archie@archie
您可以使用
pd.read\u csv()
和来编辑()
:
收益率:
{'Tom': {'name': 'Tom Techie', 'phone': '123 123546', 'email': 'tom@tom.fi', 'skype': 'skypenick'}, 'Mike': {'name': 'Mike Mechanic', 'phone': '000 123456', 'email': 'mike@mike.fi', 'skype': '-Mike-M-'}, 'Archie': {'name': 'Archie Architect', 'phone': '050 987654', 'email': 'archie@archie', 'skype': nan}}
您可以使用以下方法来实现您的目标:
file = """key;name;phone;email;skype
Tom;Tom Techie;123 123546;tom@tom.fi;skypenick
Mike;Mike Mechanic;000 123456;mike@mike.fi;-Mike-M-
Archie;Archie Architect;050 987654;archie@archie""".splitlines()
d = {}
h = None
for i in file: # works the same for your csv-file
# first row == header, store in h
if h is None:
h = i.strip().split(";")[1:]
continue # done for first row
x = i.strip().split(";")
# zip pairs the read in line with the header line to get tuples
# wich are fed into the dict constructor that creates the inner dict
d[x[0]] = dict(zip(h,x[1:]+[""])) # no default for skype
# use this instead if you want the skype key always present with empty default
# d[x[0]] = dict(zip(h,x[1:]+[""]))
print(d)
丢弃较长列表中的元素-不需要对此进行任何检查
输出:
{'Tom': {'name': 'Tom Techie', 'phone': '123 123546',
'email': 'tom@tom.fi', 'skype': 'skypenick'},
'Mike': {'name': 'Mike Mechanic', 'phone': '000 123456',
'email': 'mike@mike.fi', 'skype': '-Mike-M-'},
'Archie': {'name': 'Archie Architect', 'phone': '050 987654',
'email': 'archie@archie'}}
{'Archie': {'email': 'archie@archie',
'name': 'Archie Architect',
'phone': '050 987654',
'skype': None},
'Mike': {'email': 'mike@mike.fi',
'name': 'Mike Mechanic',
'phone': '000 123456',
'skype': '-Mike-M-'},
'Tom': {'email': 'tom@tom.fi',
'name': 'Tom Techie',
'phone': '123 123546',
'skype': 'skypenick'}}
如果您使用注释行,数据将获得skype的默认值
'
-仅适用于b/c skype是分割行的最后一个元素您可以使用dict!假设数据是
with open("df.csv", "r") as file:
d = {x.split(";")[0]:{
"name": x.split(";")[2],
"phone": x.split(";")[3],
"email": x.split(";")[1],
"skype": x.split(";")[4][:-1] # Slice off trailing newline
} for x in file}
d.pop("")
我们希望尽可能使用和打开文件,以从Python的上下文管理中获益。有关with
语句的基本理解,请参阅
由于键“
只在csv的开头出现一次,因此我们可以在末尾弹出它,避免在每次迭代时执行比较。口述理解完成了你想通过d.update
实现的相同目标
更多关于理解:
编辑:重构以删除对的重复调用。拆分可以如下所示:
contacts = {"Tom": {"name": "Tom Techie",
"phone": "123 123546",
"email": "tom@tom.fi",
"skype": "skypenick"},
"Mike": {"name": "Mike Mechanic",
"phone": "000 123546",
"email": "mike@mike.fi",
"skype": "-Mike-M-"}}
def line_to_dict(x, d):
x = x.split(";")
d[x[0]] = {
"name": x[2],
"phone": x[3],
"email": x[1],
"skype": x[4][:-1] # Slice off trailing newline
}
with open("df.csv", "r") as file:
d = {}
for x in file:
line_to_dict(x, d)
d.pop("")
我喜欢熊猫的回答,但如果你不想要第三方库,请使用内置的csv
模块:
import csv
from pprint import pprint
D = {}
with open('csv',newline='') as f:
r = csv.DictReader(f,delimiter=';')
for line in r:
name = line['key']
del line['key']
D[name] = dict(line)
pprint(D)
输出:
{'Tom': {'name': 'Tom Techie', 'phone': '123 123546',
'email': 'tom@tom.fi', 'skype': 'skypenick'},
'Mike': {'name': 'Mike Mechanic', 'phone': '000 123456',
'email': 'mike@mike.fi', 'skype': '-Mike-M-'},
'Archie': {'name': 'Archie Architect', 'phone': '050 987654',
'email': 'archie@archie'}}
{'Archie': {'email': 'archie@archie',
'name': 'Archie Architect',
'phone': '050 987654',
'skype': None},
'Mike': {'email': 'mike@mike.fi',
'name': 'Mike Mechanic',
'phone': '000 123456',
'skype': '-Mike-M-'},
'Tom': {'email': 'tom@tom.fi',
'name': 'Tom Techie',
'phone': '123 123546',
'skype': 'skypenick'}}
你的问题没有足够的信息a)运行代码,b)重现问题,c)帮助你。你至少应该提供csv文件的前几行,编辑简历的前几行,以打开帖子