用python度量代码计时。我做错了什么？

我查找时间模块，但作为新手很难阅读它。我已经在搜索一个答案，它是测量代码的开始和结束。结果是0.0。请帮我解决这个问题。

您使用时间的方式没有问题。

时间

打印

0.0

的原因是代码运行得太快，计时器根本没有改变

为了说明我的观点，我已经将您的代码循环了1000次

import time
s = time.time()
def insertionSort(alist):
    for index in range(1, len(alist)):

        currentvalue = alist[index]
        position = index

        while position > 0 and alist[position - 1] > currentvalue:
            alist[position] = alist[position - 1]
            position = position - 1

        alist[position] = currentvalue
alist = [54,26,93,17,77,31,44,55,20]
insertionSort(alist)
print (time.time() - s) # Result 0.0

输出：

import time
s = time.time()
def insertionSort(alist):
    for index in range(1, len(alist)):

        currentvalue = alist[index]
        position = index

        while position > 0 and alist[position - 1] > currentvalue:
            alist[position] = alist[position - 1]
            position = position - 1

        alist[position] = currentvalue
for x in xrange(1000):
    insertionSort([54,26,93,17,77,31,44,55,20])
e = time.time()
print (e - s) 

import timeit
t = timeit.Timer("insertionSort([54,26,93,17,77,31,44,55,20])", "from __main__ import insertionSort")
time = t.timeit(1000)
print(time)

库中有一个名为

timeit

的bulti，如果您对代码性能感兴趣，它在这种情况下非常有用

0.00600004196167

输出：

import time
s = time.time()
def insertionSort(alist):
    for index in range(1, len(alist)):

        currentvalue = alist[index]
        position = index

        while position > 0 and alist[position - 1] > currentvalue:
            alist[position] = alist[position - 1]
            position = position - 1

        alist[position] = currentvalue
for x in xrange(1000):
    insertionSort([54,26,93,17,77,31,44,55,20])
e = time.time()
print (e - s) 

import timeit
t = timeit.Timer("insertionSort([54,26,93,17,77,31,44,55,20])", "from __main__ import insertionSort")
time = t.timeit(1000)
print(time)

---

它完成得太快，无法注册；尝试多次运行排序（确保在循环中初始化数组）。此外，还可以使用来衡量绩效。（或）你期待什么？是的！非常感谢Alex！