Python Post请求保持活动状态

我试图使请求保持活动状态，但是，每次我尝试这样做时，它都会在不活动的情况下执行。我该怎么做呢？

要利用keep alive，您必须重用同一个会话。否则，requests/urllib3将无法自动跟踪您以前的请求

为此，您应该使用

requests.Session

并在请求中重用它。如中所述，“保持活动”将自动执行

将向您展示一个使用

requests.Session

的示例

import random
from colorama import Fore

file = open("valid.txt", "r+")
codes = file.readlines()


def send():
    headers = {
        "Connection": "Keep-Alive",
        "Keep-Alive": "timeout=100, max=1000"
    }
    params = {
        "cv": "4.6.19178.0323",
        "mn": "304172829",
        "pwd": "492525",
        "source": "client",
        "uname": "gregory"
    }

    url = "https://www3.zoom.us/conf/j"
    try:
        r = requests.post(url, params=params, headers=headers)
        print(Fore.GREEN + "Spammed!")
    except:
        print(Fore.RED + "Nope")


send()