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Python Django-将不同模型的信息显示到同一HTML模板中_Python_Html_Mysql_Django_View - Fatal编程技术网

Python Django-将不同模型的信息显示到同一HTML模板中

Python Django-将不同模型的信息显示到同一HTML模板中,python,html,mysql,django,view,Python,Html,Mysql,Django,View,我正在使用Django和MySQL数据库 因此,我知道views.py中的1个视图与1个HTML模板相关联,并且我无法将2个不同的视图与同一个模板相关联。 我试图创建一个“关于”视图,其中包含关于我的数据库的一些统计信息。 不幸的是,它不起作用 以下是我迄今为止为“关于”的观点所做的工作: 这是在我的终端中返回的错误: Unhandled exception in thread started by <function wrapper at 0x7f25cf87a9b0> Trace

我正在使用Django和MySQL数据库 因此,我知道views.py中的1个视图与1个HTML模板相关联,并且我无法将2个不同的视图与同一个模板相关联。 我试图创建一个“关于”视图,其中包含关于我的数据库的一些统计信息。 不幸的是,它不起作用

以下是我迄今为止为“关于”的观点所做的工作:

这是在我的终端中返回的错误:

Unhandled exception in thread started by <function wrapper at 0x7f25cf87a9b0>
Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/django/utils/autoreload.py", line 226, in wrapper
    fn(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/commands/runserver.py", line 121, in inner_run
    self.check(display_num_errors=True)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 374, in check
    include_deployment_checks=include_deployment_checks,
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 361, in _run_checks
    return checks.run_checks(**kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/registry.py", line 81, in run_checks
    new_errors = check(app_configs=app_configs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 14, in check_url_config
    return check_resolver(resolver)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 24, in check_resolver
    for pattern in resolver.url_patterns:
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 313, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 306, in urlconf_module
    return import_module(self.urlconf_name)
  File "/usr/lib/python2.7/importlib/__init__.py", line 37, in import_module
    __import__(name)
  File "/home/yoann/Projet_BD_M2BI/PDBWebsite/PDBWebsite/urls.py", line 18, in <module>
    from pdbapp.views import *
  File "/home/yoann/Projet_BD_M2BI/PDBWebsite/pdbapp/views.py", line 52
    'pdbcount': pdbcount
             ^
SyntaxError: invalid syntax
我的观点的语法对我来说似乎很好

有人建议我应该像这样在我的视图函数中添加“poll_id”:

def about(request,poll_id):
这是什么“民意测验”?这是从哪里来的


如果有人知道发生了什么,我将非常感谢您提供详细的答案/解决方案,因为我是Django的初学者。

您缺少逗号:

context = {
    'namelist': namelist,
    'pdbcount': pdbcount,
    'structcount': structcount
} 

有人跑得真快!非常感谢你的回答,我觉得自己好笨。。。
def about(request,poll_id):
context = {
    'namelist': namelist,
    'pdbcount': pdbcount,
    'structcount': structcount
}