Python 十个绿色瓶子计划

我正在用Python编写一个程序，根据用户输入的瓶子数量打印十个绿色瓶子程序。这就是我目前所拥有的

x=input("How many bottles to start with?\n")                                                    
while x > 0:                                                    
  if(x==1):                                                 
    print (str(x) + " "+"green bottle, hanging on the wall")                                                    
    print (str(x) + " "+ "green bottle hanging on the wall")                                                    
    print ("and if one green bottle, should accidentally falls")                                                    
    x = x - 1                                                   
    print("there'd be no green bottle hanging on the wall")                                                 
    print("\n")                                                 
  elif(x==2):                                                   
    print (str(x) + " "+"green bottles, hanging on the wall")                                                   
    print (str(x) + " "+ "green bottles hanging on the wall")                                                   
    print ("and if one green bottle should accidentally fall")                                                  
    x = x - 1                                                   
    print ("there'd be "  + str (x)  + " green bottle, hanging on the wall")                                                    
    print("\n")                                                 
  else:                                                 
    print (str(x) + " "+"green bottles, hanging on the wall")                                                   
    print (str(x) + " "+ "green bottles hanging on the wall")                                                   
    print ("and if one green bottle should accidentally falls")                                                 
    x = x - 1                                                   
    print ("there'd be "  + str (x)  + " green bottles, hanging on the wall")                                                   
    print("\n")                                                 
  

---

问题1：我还需要将“1”改为“1”。我正在考虑写一个函数，因为我只需要将1改为10。请告诉我如何做到这一点。

要将数字转换为各自的英语单词，建议使用字典：

x = int(input("How many bottles to start with?\n")) # Convert the input to an int
int_to_str = {
1: "one",
2: "two",
...
10: "ten"
}
print ("there'd be "  + int_to_str[x] + " green bottles, hanging on the wall")

看看如何通过使用小功能消除冗余。

问题1 这可以简单地用if语句完成。因为你提到你只需要1到10，所以声明应该是这样的

x=int（输入（“开始时有多少瓶？”）
如果（x>10或x<1）：
打印（f“不能以{x}瓶开始。请选择1到10之间的数字。”）
退出（）

问题2 这可以用字典来完成

map\u to\u str={
0:“否”，
1:"一",，
二:"两个",，
三:"三",，
四:"四",，
五:"五",，
6:“六”，
七:"七",，
八:"八",，
9:“九”，
10:“十”
}

代码的另一个问题是大量代码被不必要地重复。首先，我将使用for循环。我还将编写一个函数，将瓶子数作为字符串返回

def瓶到def瓶（def瓶的数量）：
返回f“{map_to_str[num_of_瓶子]}绿色瓶子“+”s*（num_of_瓶子！=1）

此函数将数字作为参数，并使用字典将其转换为字符串。它还检查瓶子数是否不等于1（False也可以解释为0，True解释为1）。如果瓶数不是1，则计算为

“s”*1

，即

“s”

，否则计算为

“s”*0

，即空字符串

“

主循环将如下所示

范围（x，0，-1）内的i的

：
印刷品（悬挂在墙上的“{瓶子_至_str（i）}”）
印刷品（悬挂在墙上的“{瓶子_至_str（i）}”）
打印（f“如果一个绿色瓶子意外掉落，”）
打印（f“将有{瓶子{u到{u str（i-1）}挂在墙上\n”）

为了处理这个问题，我会编写一个字典，用整数作为键和写数的值

a_python_dictionary = {'key_some_name1' : 'value_some_value1',
                       'key_some_name2' : 'value_some_value2'}

Example:
number_dict = {0:'zero', 1:'one', 2:'two',
                     ...etc...,
               8:'eight', 9:'nine', 10:'ten'}

接下来，用f-strings（一种字符串格式）编写将使用字典的函数

因此，在这个函数中发生的是：

"""
Line 1.
    def greenbottles(info=number_dict):
        defines a function called 'greenbottles' and presets a keyword argument of
        'info' equal to premade dictionary variable called 'number_dict'
Line 2.
    user_input = input("Please enter a whole number.\n")
        makes a variable inside the function called 'user_input' and prompts the
        user to enter a number. Now, this make the variable a defaulted string.
Line 3.
    try:
        this command will attempt to run thru the next lines of code indented under
        'try:'. If it returns an error, it will pass to the exception line 'except:'
Line 4:
    user_input = int(user_input)
        takes the 'user_input' variable and converts the data type to 'int' an integer
Line 5:
    while user_input > 0:
        starts a 'while loop', meaning while condition is true, do this.. the
        conditional is 'user_input' greater than '0'?
Line 6:
    if user_input >= 2:
        conditional inside the while, is 'user_input' greater than or equal to '2'
Line 7:
    print(f"{(info[user_input]).capitalize()} blah plural")
        if lines 5 & 6 result in True, print to the screen, this f-string.
        the f-string will format logic result inside '{}' to a string,
        with the rest of the string.
        Python uses a first in, first out approach.
          if the variable 'user_input' equals integer 5 
          ...a step by step break down of the line...
            print(f"{(info[user_input]).capitalize()} plural sentence")
                    ~turns into~
            print(f"{(info[5]).capitalize()} your plural sentence")
                    ~turns into~
            print(f"{('five').capitalize()} your plural sentence")
                    ~turns into~
            print(f"{'Five'} your plural sentence")
                    ~turns into~
            print("Five your plural sentence")
Line 8:
    user_input -= 1
        take value of variable and make it equal to 1 less than original value
Line 9:
    else:
        when Line 6 'if' conditional is not true, do this
Line 10:
    print(f"{(info[user_input]).capitalize()} your singular sentence")
        if Line 5 results in True, but Line 6 results in False 
        print to the screen, this f-string.
        the f-string will format logic result inside '{}' to a string,
        with the rest of the string.
        Python uses a first in, first out approach.
          the variable 'user_input' will only equal integer 1 
          ...a step by step break down of the line...
            print(f"{(info[user_input]).capitalize()} your singular sentence")
                    ~turns into~
            print(f"{(info[1]).capitalize()} your singular sentence")
                    ~turns into~
            print(f"{('one').capitalize()} your singular sentence")
                    ~turns into~
            print(f"{'One'} your singular sentence")
                    ~turns into~
            print("One your singular sentence")
Line 11:
    user_input -= 1
        take value of variable and make it equal to 1 less than original value
Line 12:
    print("There are no more bottles.")
        when Line 5 returns false, it ends while loop and print to the screen,
        'There are no more bottles.'
Line 13:
    except:
        if for any reason Lines 4 thru 12 return a error, do this...
        otherwise skip
Line 14:
    print("You did not enter a number.")
        most likely cause, is user didn't enter a number, print that message to
        screen.
"""
# Bonus
# using triple quotation marks, single or double: '''some text''' """some text"""
# are great ways of making multi-line strings, you can even use formatting
f'''some text {1+1} 
some more text'''
f"""some text {2+1} 
some more text {1+1}"""
# so, instead of using multi 'print' statements, use one...
print(f"""Here's a mulit-line
{'f-string'.capitalize()} with
some formating {'of'.upper()}
{'things '*3},
as a {'EXAMPLE'.lower()}.
""")

---

我希望这有助于您以及您对python的理解D

建议您如何编写函数。只需补充说明，python输入默认为字符串，当然可能需要使用int（x）索引。我习惯将数字输入转换为浮点或int，所以我忽略了这一点。谢谢

def greenbottles(info=number_dict):
    user_input = input("Please enter a whole number.\n")
    try:
        user_input = int(user_input)
        while user_input > 0:
            if user_input >= 2:
                print(f"{(info[user_input]).capitalize()} your plural sentence")
                user_input -= 1
            else:
                print(f"{(info[user_input]).capitalize()} your singular sentence")
                user_input -= 1
        print("There are no more bottles.")
    except:
        print("You did not enter a number.")

"""
Line 1.
    def greenbottles(info=number_dict):
        defines a function called 'greenbottles' and presets a keyword argument of
        'info' equal to premade dictionary variable called 'number_dict'
Line 2.
    user_input = input("Please enter a whole number.\n")
        makes a variable inside the function called 'user_input' and prompts the
        user to enter a number. Now, this make the variable a defaulted string.
Line 3.
    try:
        this command will attempt to run thru the next lines of code indented under
        'try:'. If it returns an error, it will pass to the exception line 'except:'
Line 4:
    user_input = int(user_input)
        takes the 'user_input' variable and converts the data type to 'int' an integer
Line 5:
    while user_input > 0:
        starts a 'while loop', meaning while condition is true, do this.. the
        conditional is 'user_input' greater than '0'?
Line 6:
    if user_input >= 2:
        conditional inside the while, is 'user_input' greater than or equal to '2'
Line 7:
    print(f"{(info[user_input]).capitalize()} blah plural")
        if lines 5 & 6 result in True, print to the screen, this f-string.
        the f-string will format logic result inside '{}' to a string,
        with the rest of the string.
        Python uses a first in, first out approach.
          if the variable 'user_input' equals integer 5 
          ...a step by step break down of the line...
            print(f"{(info[user_input]).capitalize()} plural sentence")
                    ~turns into~
            print(f"{(info[5]).capitalize()} your plural sentence")
                    ~turns into~
            print(f"{('five').capitalize()} your plural sentence")
                    ~turns into~
            print(f"{'Five'} your plural sentence")
                    ~turns into~
            print("Five your plural sentence")
Line 8:
    user_input -= 1
        take value of variable and make it equal to 1 less than original value
Line 9:
    else:
        when Line 6 'if' conditional is not true, do this
Line 10:
    print(f"{(info[user_input]).capitalize()} your singular sentence")
        if Line 5 results in True, but Line 6 results in False 
        print to the screen, this f-string.
        the f-string will format logic result inside '{}' to a string,
        with the rest of the string.
        Python uses a first in, first out approach.
          the variable 'user_input' will only equal integer 1 
          ...a step by step break down of the line...
            print(f"{(info[user_input]).capitalize()} your singular sentence")
                    ~turns into~
            print(f"{(info[1]).capitalize()} your singular sentence")
                    ~turns into~
            print(f"{('one').capitalize()} your singular sentence")
                    ~turns into~
            print(f"{'One'} your singular sentence")
                    ~turns into~
            print("One your singular sentence")
Line 11:
    user_input -= 1
        take value of variable and make it equal to 1 less than original value
Line 12:
    print("There are no more bottles.")
        when Line 5 returns false, it ends while loop and print to the screen,
        'There are no more bottles.'
Line 13:
    except:
        if for any reason Lines 4 thru 12 return a error, do this...
        otherwise skip
Line 14:
    print("You did not enter a number.")
        most likely cause, is user didn't enter a number, print that message to
        screen.
"""
# Bonus
# using triple quotation marks, single or double: '''some text''' """some text"""
# are great ways of making multi-line strings, you can even use formatting
f'''some text {1+1} 
some more text'''
f"""some text {2+1} 
some more text {1+1}"""
# so, instead of using multi 'print' statements, use one...
print(f"""Here's a mulit-line
{'f-string'.capitalize()} with
some formating {'of'.upper()}
{'things '*3},
as a {'EXAMPLE'.lower()}.
""")