Python 如何解决此问题。I';我试图使用len函数,但它';It’没有按预期工作 def mult(编号): 返回[10]*len(数字) 数字=[1,2,5,6,7,8,10] mult(编号)
我希望输出Python 如何解决此问题。I';我试图使用len函数,但它';It’没有按预期工作 def mult(编号): 返回[10]*len(数字) 数字=[1,2,5,6,7,8,10] mult(编号),python,list,Python,List,我希望输出[10,20,50……] 但这是我得到的输出[10,10,10,10,10,10,10]我就是这样做的 def mult(numbers): return [10*i for i in numbers] number = [1,2,5,6,7,8,10] mult(number) 您的方法只是获取值10,并复制与输入数组的len相等的次数。以下是您正在做的事情,注释: def mult(numbers): return [10] * len(numbers)
[10,20,50……]
但这是我得到的输出
[10,10,10,10,10,10,10]
我就是这样做的
def mult(numbers):
return [10*i for i in numbers]
number = [1,2,5,6,7,8,10]
mult(number)
您的方法只是获取值
10
,并复制与输入数组的len
相等的次数。以下是您正在做的事情,注释:
def mult(numbers):
return [10] * len(numbers)
# [10] --> Take the list [10]
# len(numbers) --> Take the length of the list `numbers`, which has 7 elements
# [10] * len(numbers) --> repeat [10] seven times, to get [10, 10, 10, 10, 10, 10, 10]
我认为问题在于您误解了len()
函数的功能,以及*
(乘法)运算符如何处理列表。如果要将每个数字乘以10,可以执行以下操作:
def mult(numbers):
multed = [] # create an empty list to store the result
for num in numbers: # iterate through the elements in `numbers` one by one
multed.append(10 * num) # add (10 * element) to our new list
return multed # return the list we've created
Python还提供了列表理解,使代码更加简洁:
def mult(numbers):
return [10*num for num in numbers]
# this does the same thing as above
我想你应该这样试试
def mult(number):
return 10 * number
number = [1,2,5,6,7,8,10]
answer = []
for i in number:
answer.append(mult(i))
print(answer)
这不是len()
所做的(显然)。如果尚未完成,则应完成以下步骤: