Python：对列表进行计数并显示计数范围

所以我有一个列表，有两个数字，分别是1和0。列表中的每一项都相当于1秒的音频。0是语音，1是音乐

列表示例：

[1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,1,1,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,1,1,1,1,1]

我希望输出显示音频的开始、结束和音频的类型

输出：

1,6,    music 
7,12,   speech
13,17,  music
18,24,  speech
25,26,  music
27,32,  speech
33,37,  music

输出：

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你的尝试有什么不起作用？你的问题是什么？请看第页投票率最高答案的第二部分。它与你想要的东西“相似”，谢谢你的帮助。这正是我想要输出的样子。谢谢你的帮助。

a = [1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,1,1,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,1,1,1,1,1]
changes = [i+1 for i,val in enumerate(a[:-1]) if val != a[i+1]]
lists_start_end = [(1,changes[0])] + [(val+1,changes[i+1]) for i,val in enumerate(changes[:-1])] + [(changes[-1],len(a))]

[(1, 6), (7, 12), (13, 17), (18, 24), (25, 26), (27, 32), (32, 37)]

In[2]: data = [1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1]
In[3]: from itertools import groupby
  ...: 
  ...: dex = 1
  ...: result = []
  ...: for k, g in groupby(data):
  ...:     length = sum(1 for _ in g)
  ...:     result.append((
  ...:         (dex, dex + length - 1),
  ...:         'music' if k == 1 else 'speech'
  ...:     ))
  ...:     dex += length
  ...: 
In[4]: result
Out[4]: 
[((1, 6), 'music'),
 ((7, 12), 'speech'),
 ((13, 17), 'music'),
 ((18, 24), 'speech'),
 ((25, 26), 'music'),
 ((27, 32), 'speech'),
 ((33, 37), 'music')]