Python 使用twitter JSON响应

Python 使用twitter JSON响应,python,json,python-2.7,twitter,Python,Json,Python 2.7,Twitter,我正在使用twitterapi和python,当我试图合并检索到的JSON页面时,遇到了一个问题 为每个请求检索的JSON的结构为: { "previous_cursor": 0, "previous_cursor_str": "0", "next_cursor": 1333504313713126852, "users": [ { "foo": "bar", "foo": "bar", "foo": "

我正在使用twitterapi和python,当我试图合并检索到的JSON页面时,遇到了一个问题

为每个请求检索的JSON的结构为:

{
  "previous_cursor": 0,
  "previous_cursor_str": "0",
  "next_cursor": 1333504313713126852,
  "users": [
        {
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar"
         },
         {
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar"
         },
         {
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar",
          "foo": "bar"
         }
     ],
     "next_cursor_str": "1333504313713126852"
}
我需要将所有数据合并到一个包含每个用户信息的列表中。问题是,当我这样做时,我得到了以下结构:

friends_list = [friends_list, raw_friends_list['users']]

[
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
]
[
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
]    
而不是:

[
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
    {"foo": "bar","foo": "bar"}
]  
有人知道用python实现这一点的正确方法吗

问候,

friends_list.extend(raw_friends_list['users'])