Python matplotlib,plt.show()在其他方法中=单击时为否

Python matplotlib,plt.show()在其他方法中=单击时为否,python,matplotlib,matplotlib-widget,Python,Matplotlib,Matplotlib Widget,当我用另一种方法放置plt.show()时,无法单击按钮: import matplotlib.pyplot as plt from matplotlib.widgets import Button class ButtonTest: def __init__(self): ax = plt.axes([0.81, 0.05, 0.1, 0.075]) bnext = Button(ax, 'Next') bnext.on_clicked

当我用另一种方法放置plt.show()时,无法单击按钮:

import matplotlib.pyplot as plt
from matplotlib.widgets import Button

class ButtonTest:
    def __init__(self):
        ax = plt.axes([0.81, 0.05, 0.1, 0.075])
        bnext = Button(ax, 'Next')
        bnext.on_clicked(self._next)
#         plt.show()

    def show(self):
        print("when i put plt.show() in a different method, it's impossible to click the button")
        plt.show()

    def _next(self, event):
        print("next !")

b = ButtonTest()
b.show()

当鼠标移到按钮上时,按钮甚至不会高亮显示。有人知道为什么以及如何解决这个问题吗?

发生的事情是,在显示绘图之前,button对象正在被垃圾收集。你需要保留对它的引用

例如,如果你改变

bnext = Button(...)

一切都会好起来的

作为一个完整的例子:

import matplotlib.pyplot as plt
from matplotlib.widgets import Button

class ButtonTest:
    def __init__(self):
        ax = plt.axes([0.81, 0.05, 0.1, 0.075])
        self.bnext = Button(ax, 'Next')
        self.bnext.on_clicked(self._next)

    def show(self):
        plt.show()

    def _next(self, event):
        print("next !")

ButtonTest().show()
import matplotlib.pyplot as plt
from matplotlib.widgets import Button

class ButtonTest:
    def __init__(self):
        ax = plt.axes([0.81, 0.05, 0.1, 0.075])
        self.bnext = Button(ax, 'Next')
        self.bnext.on_clicked(self._next)

    def show(self):
        plt.show()

    def _next(self, event):
        print("next !")

ButtonTest().show()