Python matplotlib,plt.show()在其他方法中=单击时为否
当我用另一种方法放置plt.show()时,无法单击按钮:Python matplotlib,plt.show()在其他方法中=单击时为否,python,matplotlib,matplotlib-widget,Python,Matplotlib,Matplotlib Widget,当我用另一种方法放置plt.show()时,无法单击按钮: import matplotlib.pyplot as plt from matplotlib.widgets import Button class ButtonTest: def __init__(self): ax = plt.axes([0.81, 0.05, 0.1, 0.075]) bnext = Button(ax, 'Next') bnext.on_clicked
import matplotlib.pyplot as plt
from matplotlib.widgets import Button
class ButtonTest:
def __init__(self):
ax = plt.axes([0.81, 0.05, 0.1, 0.075])
bnext = Button(ax, 'Next')
bnext.on_clicked(self._next)
# plt.show()
def show(self):
print("when i put plt.show() in a different method, it's impossible to click the button")
plt.show()
def _next(self, event):
print("next !")
b = ButtonTest()
b.show()
当鼠标移到按钮上时,按钮甚至不会高亮显示。有人知道为什么以及如何解决这个问题吗?发生的事情是,在显示绘图之前,button对象正在被垃圾收集。你需要保留对它的引用 例如,如果你改变
bnext = Button(...)
到
一切都会好起来的
作为一个完整的例子:
import matplotlib.pyplot as plt
from matplotlib.widgets import Button
class ButtonTest:
def __init__(self):
ax = plt.axes([0.81, 0.05, 0.1, 0.075])
self.bnext = Button(ax, 'Next')
self.bnext.on_clicked(self._next)
def show(self):
plt.show()
def _next(self, event):
print("next !")
ButtonTest().show()
import matplotlib.pyplot as plt
from matplotlib.widgets import Button
class ButtonTest:
def __init__(self):
ax = plt.axes([0.81, 0.05, 0.1, 0.075])
self.bnext = Button(ax, 'Next')
self.bnext.on_clicked(self._next)
def show(self):
plt.show()
def _next(self, event):
print("next !")
ButtonTest().show()