Python 跨多列返回最后日期和名称的值

我有这个1000x6的数据帧。如何添加另外两列：列[latest person]，列[latest date]以显示姓氏和姓名 行动日期/时间

输入：

    Reviewer 3   Action Date / Time.2       Approver 1   Action Date / Time.3        Approver 2   Action Date / Time.4


3970          0                      0      Pat McEntee  10.04.2018 - 11:01:55                 0                      0
3971  John Hunt  12.04.2018 - 17:07:54  Paul Monnington  24.04.2018 - 16:22:17                 0                      0
3974          0                      0       Mike Smith  16.04.2018 - 09:30:06                 0                      0
3975          0                      0   Peter McNamara  13.04.2018 - 16:15:27  Stephen Harrison  20.04.2018 - 11:32:39
3977          0                      0   Ananth Sarathy  17.04.2018 - 17:37:03                 0                      0
3978  John Hunt  19.04.2018 - 09:08:12    Sandra Osteni  19.04.2018 - 09:12:38   Amanda Bardwell  01.05.2018 - 09:01:20
3979  John Hunt  19.04.2018 - 09:08:12    Sandra Osteni  19.04.2018 - 09:09:36   Amanda Bardwell  01.05.2018 - 09:02:08
3980  John Hunt  19.04.2018 - 09:08:12    Sandra Osteni  19.04.2018 - 09:13:01   Amanda Bardwell  01.05.2018 - 09:00:49
3981  John Hunt  17.04.2018 - 15:52:58    Sandra Osteni  19.04.2018 - 09:11:58   Amanda Bardwell  01.05.2018 - 09:00:17
3982  John Hunt  17.04.2018 - 15:52:01    Sandra Osteni  19.04.2018 - 09:11:22   Amanda Bardwell  01.05.2018 - 09:01:34
3984          0                      0       Mike Smith  04.05.2018 - 14:51:58                 0                      0
...
4012          0                      0      Trent Mason  23.04.2018 - 12:56:04        Mike Smith  23.04.2018 - 15:03:06
4013          0                      0      Trent Mason  23.04.2018 - 12:57:26        Mike Smith  23.04.2018 - 15:14:41
4014          0                      0      Trent Mason  23.04.2018 - 12:56:58        Mike Smith  23.04.2018 - 15:15:46
4015          0                      0      Trent Mason  23.04.2018 - 12:56:45        Mike Smith  23.04.2018 - 15:05:52
4016          0                      0      Trent Mason  23.04.2018 - 12:57:40        Mike Smith  23.04.2018 - 15:03:39
4017          0                      0      Trent Mason  23.04.2018 - 12:55:14        Mike Smith  23.04.2018 - 15:04:52
4018  John Hunt  23.04.2018 - 10:29:59    Sandra Osteni  30.04.2018 - 13:09:01     Sandra Osteni  30.04.2018 - 13:09:19
4019          0                      0      Trent Mason  23.04.2018 - 12:55:50        Mike Smith  23.04.2018 - 15:09:18

期望输出：

 Latest person  Latest date

  Pat McEntee      10.04.2018 - 11:01:55
  Paul Monnington  24.04.2018 - 16:22:17 
  Mike Smith       16.04.2018 - 09:30:06
  Stephen Harrison 20.04.2018 - 11:32:39
  Ananth Sarathy   17.04.2018 - 17:37:03
...
  Sandra Osteni    30.04.2018 - 13:09:19
  Mike Smith       23.04.2018 - 15:09:18

---

看起来您希望获得最右边的列对，即

最新的person/date

。为了快速实现这一点，在将

0

替换为

NaN

后，按列向前填充，并获取新列的最右侧信息

import numpy as np

df = df.replace("0", np.nan)

persons = df[df.columns[::2]].fillna(axis=1, method='ffill')
dates = df[df.columns[1::2]].fillna(axis=1, method='ffill')

df['Latest person'] = persons[persons.columns[-1]]
df['Latest date'] = dates[dates.columns[-1]]

---

菲尔真是个好主意！我试图得到包含日期的单元格布尔值，但你的更复杂。：）谢谢@Candice，yw，我简化了代码，因为我注意到我的初始表达式有点多余。