R中的If、else If、else语句和逻辑运算符以及创建函数

这件事我已经做了两天了，我简直是陷在泥里了！我正在研究在R中使用if、elseif和else语句

我创建了一个函数，可以为两名玩家随机抽取3张卡来模拟一场游戏

face=c("king", "queen", "jack", "ten", "nine", "eight", "seven", "six", "five", "four", "three", "two", "ace")
value=c(13, 12,11,10,9,8,7,6,5,4,3,2,1) 
deck <-data.frame(face=rep(face,4),
                  suit=c(rep("spades", 13), rep("clubs", 13), rep("diamonds", 13), rep("hearts", 
                  13)),
                  value=rep(value,4)) 

这是我的if语句

combo.1=c("ace", "ace", "ace")
combo.2=c("heart", "heart", "heart")

if (Sum.Player.A==combo.1){
  Sum.Player.A<-Sum.Player.A*2
}else{
  Sum.Player.A
}

if(Sum.Player.A==combo.2){
  Sum.Player.A<-Sum.Player.A*2
}else{
  Sum.Player.A
}

if (Sum.Player.B==combo.1){
  Sum.Player.B<-Sum.Player.B*2
}else{
  Sum.Player.B
}

if(Sum.Player.B==combo.2){
  Sum.Player.B<-Sum.Player.B*2
}else{
  Sum.Player.B
}

if（Sum.Player.A==combo.1）{
Sum.Player.A我在牌组的创建中添加了stringsAsFactors=FALSE。抽n张随机牌一次抽牌，否则你就有抽相同牌的风险（需要不替换地完成）。最后，winner函数将A手牌和B手牌的和作为参数

face=c("king", "queen", "jack", "ten", "nine", "eight", "seven", "six", "five", "four", "three", "two", "ace")
value=c(13, 12,11,10,9,8,7,6,5,4,3,2,1) 
deck <-data.frame(face=rep(face,4),
                  suit=c(rep("spades", 13), rep("clubs", 13), rep("diamonds", 13), rep("hearts", 
                                                                                       13)),
                  value=rep(value,4), stringsAsFactors = FALSE) 

get_cards<-function(){
  return(draw_n_random_cards(6))
}

draw_n_random_cards=function(n) {
  s=sample(1:52, 6, replace=FALSE)
  return(deck[s,])
}

winner<-function(A, B){
  if(A<B){
    "Player B is the winner"
  }else if (A>B){
    "Player A is the winner"}else {
      "tie"}
}

play_game=function() {
  cards=draw_n_random_cards()
  Player.A=cards[1:3,]
  Player.B=cards[4:6,]
  Sum.Player.A<-sum(Player.A$value)
  Sum.Player.B<-sum(Player.B$value)
  
  combo.1=c("ace", "ace", "ace")
  combo.2=c("heart", "heart", "heart")
  
  if (identical(Player.A$face, combo.1) | identical(Player.A$suit, combo.2)) {
    Sum.Player.A<-Sum.Player.A*2
  }
  if (identical(Player.B$face, combo.1) | identical(Player.B$suit, combo.2)) {
    Sum.Player.B<-Sum.Player.B*2
  }
  winner(Sum.Player.A, Sum.Player.B)
}

这很有意义。您创建了一个获取卡片的函数，该函数将返回6张卡片。
if (Sum.Player.A==combo.1){
  Sum.Player.A<-Sum.Player.A*2
}else{
  Sum.Player.A
}

if(Sum.Player.A==combo.2){
  Sum.Player.A<-Sum.Player.A*2
}else{
  Sum.Player.A
}

if (Sum.Player.B==combo.1){
  Sum.Player.B<-Sum.Player.B*2
}else{
  Sum.Player.B
}

if(Sum.Player.B==combo.2){
  Sum.Player.B<-Sum.Player.B*2
}else{
  Sum.Player.B
}

winner<-function(){
if(Sum.Player.A<Sum.Player.B){
          "Player B is the winner"
        }else if (Sum.Player.A>Sum.Player.B){
          "Player A is the winner"}else {
           "tie"}
}

play_game<-function(){

#1 draw 3 random cards for each player
#2 score their cards
#3 compare their score to delcare a winner
}

face=c("king", "queen", "jack", "ten", "nine", "eight", "seven", "six", "five", "four", "three", "two", "ace")
value=c(13, 12,11,10,9,8,7,6,5,4,3,2,1) 
deck <-data.frame(face=rep(face,4),
                  suit=c(rep("spades", 13), rep("clubs", 13), rep("diamonds", 13), rep("hearts", 
                                                                                       13)),
                  value=rep(value,4), stringsAsFactors = FALSE) 

get_cards<-function(){
  return(draw_n_random_cards(6))
}

draw_n_random_cards=function(n) {
  s=sample(1:52, 6, replace=FALSE)
  return(deck[s,])
}

winner<-function(A, B){
  if(A<B){
    "Player B is the winner"
  }else if (A>B){
    "Player A is the winner"}else {
      "tie"}
}

play_game=function() {
  cards=draw_n_random_cards()
  Player.A=cards[1:3,]
  Player.B=cards[4:6,]
  Sum.Player.A<-sum(Player.A$value)
  Sum.Player.B<-sum(Player.B$value)
  
  combo.1=c("ace", "ace", "ace")
  combo.2=c("heart", "heart", "heart")
  
  if (identical(Player.A$face, combo.1) | identical(Player.A$suit, combo.2)) {
    Sum.Player.A<-Sum.Player.A*2
  }
  if (identical(Player.B$face, combo.1) | identical(Player.B$suit, combo.2)) {
    Sum.Player.B<-Sum.Player.B*2
  }
  winner(Sum.Player.A, Sum.Player.B)
}

> play_game()
[1] "Player B is the winner"