R控制每行数据帧中连续NA值的数量

R控制每行数据帧中连续NA值的数量,r,dataframe,filter,na,missing-data,R,Dataframe,Filter,Na,Missing Data,有一些措辞类似的问题,但不完全是我想要做的 我有一个数据帧,我想删除具有n个连续NA值的行 1 Manhattan NA 2300 NA 2275 2300 2 Manhattan 2999 2975 NA NA 2995 3 Manhattan NA NA NA NA 4400 4 Manhattan 6725 6500 6

有一些措辞类似的问题,但不完全是我想要做的

我有一个数据帧,我想删除具有n个连续NA值的行

1   Manhattan   NA      2300    NA      2275    2300    
2   Manhattan   2999    2975    NA      NA      2995    
3   Manhattan   NA      NA      NA      NA      4400    
4   Manhattan   6725    6500    6750    6995    6800    
5   Brooklyn    2000    1995    1975    2000    1999    
6   Bronx       1200    3200    NA      NA      NA
我有一些工作代码,删除了n个总NA值,但想对其进行连续调整

delete.na <- function(df, n=0) {
  df[rowSums(is.na(df)) <= n,]
}
df <- delete.na(df,3)

一个选项是在行上循环,用
rle
检查以返回相同的相邻元素的值和长度列表(这里是逻辑向量(
is.na
-即TRUE-表示na,FALSE表示非na),因为“值”是逻辑的,所以使用它来子集“长度”,检查它是否小于3,并将其用作子集行的行索引

df[apply(df, 1, function(x) all(with(rle(is.na(x)), lengths[values]) <3)),]
#     city col1 col2 col3 col4 col5
#1 Manhattan   NA 2300   NA 2275 2300
#2 Manhattan 2999 2975   NA   NA 2995
#4 Manhattan 6725 6500 6750 6995 6800
#5  Brooklyn 2000 1995 1975 2000 1999
df[应用(df,1,函数(x)all(使用(rle(is.na(x)),长度[值])
df[apply(df, 1, function(x) all(with(rle(is.na(x)), lengths[values]) <3)),]
#     city col1 col2 col3 col4 col5
#1 Manhattan   NA 2300   NA 2275 2300
#2 Manhattan 2999 2975   NA   NA 2995
#4 Manhattan 6725 6500 6750 6995 6800
#5  Brooklyn 2000 1995 1975 2000 1999
df <- structure(list(city = c("Manhattan", "Manhattan", "Manhattan", 
"Manhattan", "Brooklyn", "Bronx"), col1 = c(NA, 2999L, NA, 6725L, 
2000L, 1200L), col2 = c(2300L, 2975L, NA, 6500L, 1995L, 3200L
), col3 = c(NA, NA, NA, 6750L, 1975L, NA), col4 = c(2275L, NA, 
NA, 6995L, 2000L, NA), col5 = c(2300L, 2995L, 4400L, 6800L, 1999L, 
NA)), class = "data.frame", row.names = c("1", "2", "3", "4", 
"5", "6"))