R 如何对特定时间格式的时间序列数据进行平均

R 如何对特定时间格式的时间序列数据进行平均,r,time-series,average,R,Time Series,Average,我有一个mm:ss.s形式的时间序列。我想做的是取a到c列中每1分钟的平均数据。重要的一点是,时间将在59:09.9 我不知道应该如何导入这种类型的时间值,所以为了保持数据的原样,我以字符形式导入了时间 数据如下: structure(list(DATETIME = c("00:00.5", "00:01.1", "00:01.7", "00:02.2", "00:02.8", "00

我有一个mm:ss.s形式的时间序列。我想做的是取a到c列中每1分钟的平均数据。重要的一点是,时间将在59:09.9 我不知道应该如何导入这种类型的时间值,所以为了保持数据的原样,我以字符形式导入了时间

数据如下:

structure(list(DATETIME = c("00:00.5", "00:01.1", "00:01.7", 
"00:02.2", "00:02.8", "00:03.4", "00:03.9", "00:04.5", "00:05.0", 
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52.626, 52.428, 53.547, 53.547, 52.36, 51.635, 53.348, 52.951, 
52.951, 53.419, 51.964, 52.36, 51.437, 53.944, 52.23, 51.704, 
52.032, 53.877, 52.032, 53.348, 52.23, 52.23, 53.944, 53.944, 
54.408, 54.54, 54.54, 54.341, 53.55, 52.951, 53.944, 53.082, 
53.547, 52.032, 52.032, 53.28, 53.678, 51.964, 51.964, 52.951, 
52.032, 53.28, 52.883, 51.765, 51.437, 53.023, 53.547, 52.559, 
52.428, 52.428, 52.23, 53.352, 54.274, 53.352, 53.55, 54.274, 
52.626, 54.076, 53.547, 53.221, 53.352, 53.352, 55.07, 53.419, 
53.947, 54.937, 55.268, 54.014, 55.335, 53.617, 55.533, 55.335, 
54.937, 55.865, 56.064, 53.617, 55.335, 52.354, 54.212, 53.617, 
54.937, 53.617, 54.54, 52.428, 54.54, 53.221, 53.55, 53.352, 
53.748, 54.341, 53.023, 52.428, 54.739, 54.739, 53.55, 54.341, 
52.626, 53.023, 53.023, 55.666, 52.032, 53.082, 51.635, 52.752, 
53.082, 52.951, 10.63, 8.444, 4.952, 5.253, 6.457, 6.457, 5.054, 
5.253, 6.259, 5.054, 5.054, 6.259, 6.561, 6.259, 5.355, 6.259, 
5.054, 6.259, 5.054, 5.355, 5.355, 5.054, 6.259, 6.259, 5.054, 
6.457, 5.054, 5.355, 6.561, 5.355, 5.054, 5.957, 5.054, 6.457, 
6.457, 6.759, 5.553, 5.553, 6.759, 6.759, 6.457, 5.253, 5.553, 
5.553, 5.553, 5.253, 6.457, 6.759, 6.457, 6.457, 5.253, 6.457, 
6.259, 6.457, 6.759, 6.759, 5.253, 5.253, 5.253, 5.553, 5.253, 
6.457, 6.457, 6.759, 5.553, 5.253, 6.259, 6.457, 5.054, 6.759, 
5.253, 6.457, 5.054, 6.759, 4.952, 5.553, 5.355, 6.06, 4.856, 
4.856, 4.856, 6.259, 5.157, 4.856, 6.06, 6.362, 4.856, 5.054, 
4.856, 5.157, 6.362, 6.259, 6.362, 5.157, 4.856, 4.856, 5.157, 
5.964, 4.856, 4.856, 4.46, 6.362, 6.06, 4.856, 6.06, 5.157, 6.06, 
6.06, 6.06, 5.157, 4.856, 4.856, 4.856, 6.362, 6.06, 5.157, 4.856, 
6.06, 6.259, 6.259, 6.06, 6.362, 6.362, 6.06, 6.561, 6.06, 4.76, 
4.76, 4.76, 4.76, 6.362, 6.259, 6.06, 5.054, 4.76, 5.157, 6.06, 
5.157, 5.355, 5.054, 6.06, 5.054, 4.856, 6.06, 4.856, 5.054, 
6.362, 6.06, 6.06, 5.054, 4.856, 6.362, 4.46, 6.561, 5.157, 4.856, 
4.856, 4.856, 6.561, 6.06, 6.259, 4.856, 5.157, 5.054, 5.157, 
6.06, 4.856, 5.157, 5.054, 6.06, 6.06, 5.054, 6.06, 6.362, 4.856, 
6.362, 6.06, 6.06, 4.856, 4.856, 5.361, 5.157, 6.06, 5.054, 5.157, 
5.054, 5.355, 5.054, 6.259, 4.856, 6.06, 4.856, 5.157, 6.259, 
6.06, 5.054, 5.157, 4.856, 6.362, 6.259, 4.856, 5.758, 5.157, 
6.06, 4.856, 6.06, 6.561, 6.06, 6.06, 5.054, 5.355, 5.054, 5.054, 
5.157, 6.561, 5.157, 4.856, 6.561, 4.46, 6.362, 6.06, 6.561, 
5.157, 6.06, 6.259, 4.856, 6.06, 5.355, 4.856, 6.06, 4.856, 6.06, 
5.157, 5.054, 6.06, 6.362, 5.054, 4.856, 5.157, 5.157, 5.054, 
6.259, 4.856, 6.362, 5.157, 4.856, 5.054, 6.259, 5.355, 5.157, 
6.362, 5.157, 5.355, 5.355, 6.06, 4.856, 5.157, 4.856, 5.054, 
5.355, 5.355, 5.054, 6.06, 4.856, 6.561, 6.362, 6.06, 6.06, 4.856, 
5.054, 6.06, 6.06, 5.355, 6.06, 5.157, 5.355, 4.856, 6.259, 5.054, 
5.157, 6.06, 6.06, 4.856, 6.362, 5.157, 6.561, 5.157, 5.157, 
4.856, 4.856, 6.06, 4.856, 4.856, 4.856, 6.06, 6.259, 5.157, 
5.157, 6.561, 6.561, 5.054, 6.362, 6.06, 5.157, 6.259, 5.054, 
6.06, 5.157, 5.054, 6.06, 6.259, 5.054, 6.259, 5.355, 6.06, 6.06, 
6.06, 6.259, 5.054, 5.054, 6.06, 5.054, 5.355, 6.362, 4.856, 
4.856, 6.259, 4.856, 6.259, 4.856, 6.06, 6.259, 6.06, 6.06, 6.561, 
4.856, 6.362, 6.561, 6.06, 5.157, 5.157, 4.856, 6.06, 6.561, 
6.06, 6.259, 4.856, 4.856, 6.06, 4.856, 6.362, 6.06, 4.856, 6.561, 
6.561, 4.856, 4.856, 4.856, 6.362, 6.362, 6.259, 6.362, 6.259, 
6.362, 6.06, 5.157, 6.06)), class = c("spec_tbl_df", "tbl_df", 
"tbl", "data.frame"), row.names = c(NA, -477L), spec = structure(list(
    cols = list(DATETIME = structure(list(), class = c("collector_character", 
    "collector")), a = structure(list(), class = c("collector_double", 
    "collector")), b = structure(list(), class = c("collector_double", 
    "collector")), c = structure(list(), class = c("collector_double", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

借助于
lubridate
data.table
rleid
可以执行以下操作:

library(dplyr)
library(lubridate)

df %>%
  mutate(DATETIME = ms(DATETIME)) %>%
  group_by(minutes = data.table::rleid(ceiling(period_to_seconds(DATETIME)/60))) %>%
  summarise(across(a:c, mean, na.rm = TRUE))

# minutes      a       b     c
#    <dbl>  <dbl>   <dbl> <dbl>
#1       1 0.527  53.0    53.4 
#2       2 0.0335  3.05    7.57
#3       3 0.0178  0.0139  5.54
#4       4 0.0162  0.0184  5.54
#5       5 0.0183  0.0204  5.75
库(dplyr)
图书馆(lubridate)
df%>%
突变(DATETIME=ms(DATETIME))%>%
分组依据(分钟=数据。表格::rleid(上限(时段到秒(日期时间)/60)))%>%
总结(跨越(a:c,平均值,na.rm=TRUE))
#a b c分钟
#          
#1       1 0.527  53.0    53.4 
#2       2 0.0335  3.05    7.57
#3       3 0.0178  0.0139  5.54
#4       4 0.0162  0.0184  5.54
#5       5 0.0183  0.0204  5.75
df%>%
分组依据(DATETIME=str\u extract(DATETIME,\\d{2}”))%>%
汇总所有数据(平均值,na.rm=TRUE)
#一个tibble:5x4
日期时间a b c
1 00       0.527  53.0    53.4 
2 01       0.0335  3.05    7.57
3 02       0.0178  0.0132  5.53
4 03       0.0163  0.0191  5.55
5 04       0.0183  0.0204  5.75

您是如何获得“collector\u character”或“collector\u double”类列的?似乎您并没有告诉我们有关数据处理的所有信息。@IRTFM-这些似乎是存储在
attr(dat,“spec”)
中的额外信息,可能是由于最初用于导入数据的原因。这是我得到的(
df%>%mutate(mins=minute(ms(DATETIME))%%>%groupby(mins)%%>%摘要(跨越(a:c,平均值,na.rm=TRUE))
),但如何在“59:09.9”之后将分钟重置为零?@jared_mamrot可以使用
数据。表
。更新了答案。
df %>%
   group_by(DATETIME = str_extract(DATETIME, "\\d{2}")) %>%
   summarise_all(mean, na.rm = TRUE)

# A tibble: 5 x 4
  DATETIME      a       b     c
  <chr>     <dbl>   <dbl> <dbl>
1 00       0.527  53.0    53.4 
2 01       0.0335  3.05    7.57
3 02       0.0178  0.0132  5.53
4 03       0.0163  0.0191  5.55
5 04       0.0183  0.0204  5.75