R-执行地理空间计算的最佳方式

我正在从事一个项目，在这个项目中，我从API中提取犯罪数据，基本上计算每个预定义网格单元的犯罪密度。我现在通过将lat和lon放入data.frame中，然后计算点中心半径内的点数来实现这一点。这在计算上是昂贵的，因为预定义网格中有数千个点和数千个犯罪点

我想知道是否有更好的方法来计算犯罪密度；我听说光栅可能很有价值

一些样本数据：

# Create a predefined grid of coordinates
predef.grid <- data.frame(lat = seq(from = 2.0, to = 4.0, by = 0.1),lon = seq(from = 19.0, to = 21.0, by = 0.1))
predef.grid <- expand.grid(predef.grid)

# Create random sample of crime incidents
crime.incidents <- data.frame(lat = rnorm(10, 4),lon = rnorm(10,20))
crime.incidents <- expand.grid(mydata)

# Need to count number of crimes within radius of every point in predef.grid

#创建预定义的坐标网格
predef.grid
#需要计算每个网格点半径内的犯罪数量
图书馆（光栅）
图书馆（sp）
#预先定义的光栅
预定义网格
# Need to count number of crimes within radius of every point in   
library(raster)
library(sp)

# predfined raster
predef.grid <- raster(xmn=2,  # xmin
                  ymn=4,  # ymin
                  xmx=19, # xmax
                  ymx=21, # ymax
                  res=1,  # spatial resolution
                  vals = 1) # cell value
plot(predef.grid)

# Create random sample of crime incidents
# points should be a Spatial object of some form, point, etc.
crime.incidents <- spsample(x = as(extent(predef.grid), 'SpatialPolygons'),
                        n =  100, 
                        type = 'random')

# plot points over grid
points(crime.incidents, pch = 20)

# count points per cell
density <- rasterize(crime.incidents, predef.grid, fun='count')

# plot the density 
plot(density)