Reactjs RN:构造函数与无构造函数,组件有道具
在我的Reactjs RN:构造函数与无构造函数,组件有道具,reactjs,react-native,Reactjs,React Native,在我的React Native 0.59App.js中,向每个组件传递了两个道具: const data = this.props.navigation.state.params.data; const EventWithSelf = (props) => (<Event {...props} myself={data.myself} token={data.result} />) const NeweventWithSelf = (props) => (<NewE
React Native 0.59
App.js
中,向每个组件传递了两个道具:
const data = this.props.navigation.state.params.data;
const EventWithSelf = (props) => (<Event {...props} myself={data.myself} token={data.result} />)
const NeweventWithSelf = (props) => (<NewEvent {...props} myself={data.myself} token={data.result} />)
或者我也可以不使用构造函数,如下所示:
export default class Event extends React.Component {
state = {
activeEvents: [],
user: this.props.myself,
token: this.props.token,
};
//more code.........
在没有显式构造函数的情况下,在何处初始化
此项更好。_isMounted=true
对于这种情况,您不需要有构造函数。您可以这样做:
export default class Event extends React.Component {
state = {
activeEvents: [],
user: this.props.myself,
token: this.props.token,
}
_isMounted = false
}
export default class Event extends React.Component {
state = {
activeEvents: [],
user: this.props.myself,
token: this.props.token,
}
_isMounted = false
}