Regex 正则表达式匹配行尾$在Bash脚本中不起作用

我尝试在bash脚本中执行一个简单的regex语句，它将匹配并替换单词的结尾。下面是我想做的

wordh > word:’

下面是我正在使用的代码

#!/bin/bash
STAT=${STAT/h$/:’}

---

我不熟悉bash脚本，我认为它与

$

有关，因为它用于标记变量。我试着避开它，并在它之后添加另一个

/

。当我删除

$

时，它会工作（不检查单词的结尾）。

regex的存在有些不同。 尝试：

从手册页：

${parameter/pattern/string}

.         The pattern is expanded to produce a pattern just as in pathname
          expansion.   Parameter is expanded and the longest match of pat-
          tern against its value is replaced  with  string.   If  Ipattern
          begins  with /, all matches of pattern are replaced with string.
          Normally only the first match is replaced.   If  pattern  begins
          with  #, it must match at the beginning of the expanded value of
          parameter.  If pattern begins with %, it must match at  the  end
          of  the expanded value of parameter.  If string is null, matches
          of pattern are deleted and the / following pattern may be  omit-
          ted.   If  parameter  is  @  or *, the substitution operation is
          applied to each positional parameter in turn, and the  expansion
          is  the  resultant list.  If parameter is an array variable sub-
          scripted with @ or *, the substitution operation is  applied  to
          each  member  of  the  array  in  turn, and the expansion is the
          resultant list.

---

$不是这个词的一部分

你可以试试

    STAT=wordh\$

比尝试

     STAT=${STAT/h$/:’}

---

更像是，它根本不是正则表达式。如果启用了extglob，它就是正则表达式，但默认情况下它不是。

     STAT=${STAT/h$/:’}