Ruby 如何将阵列中的多个对象铲到一个对象中？

我有一个

团队

课程：

class Team
  attr_accessor :teamplayers
  def initialize
    @team_players = []
  end
  def <<(player)  
    @team_players << player
  end
  def to_s
    puts "THIS IS THE TEAM #{@team_players}" 
  end
end

班级团队
属性访问器：团队成员
def初始化
@团队成员=[]
结束
def
您还可以在每次添加内容时展平阵列：

def <<(player)
  @team_players << player
  @team_players.flatten!
end

def t[“鲍勃”、“爱丽丝”、“乔”、“比尔”]

剩下的问题是，您是否希望通过隐式转换将
的方式缩短一点：

def <<(*player)
   @team_players.concat player.flatten
end

def只需使用
+
（或
concat
）：

问题是什么？您是否遇到了一个错误，因为您的代码似乎会按照标题的建议执行。
def <<(player)
  if player.kind_of?(Array)
    @team_players.concat player  
  else
    @team_players << player
  end
end

def <<(player)
  @team_players << player
  @team_players.flatten!
end

irb(main):032:0> t << ["Bob"]
=> ["Bob"]
irb(main):032:0> t << ["Alice", "Joe"]
=> ["Bob", "Alice", "Joe"]
irb(main):033:0> t << ["Bill"]
=> ["Bob", "Alice", "Joe", "Bill"]

def <<(*player)
   @team_players.concat player.flatten
end

team = team + @defenders[-1..-4]
#or 
team.concat(@defenders[-1..-4])