Spring 弹簧&x2B；休眠一对一映射

我正在使用spring和hibernate开发web应用程序。我正在两个表employee和PersonelDetails之间使用一对一映射

下面是我的bean类

==================================员工=====================================

@Entity
@Table(name="employee")
public class Employee {
    @Id
    @Column
    @GeneratedValue
    private int empid;
    @Column
    private String firstName;
    @Column
    private String lastName;
    @Column
    private String email;
    @Column
    private String password;
    @Column
    private boolean isAdmin;

    @Column
    private boolean isActive;

    @Column
    private boolean isLocked;
//getter setters

@Entity
@Table(name="PersonalDetails")
public class PersonalDetails {
    @Column
    @Id
    private int empid;
    @Column
    private String personalEmail;
    @Column
    private String mob;
    @Column
    private String permenantAdress;
    @Column
    private String currentAddress;
    @Column
    private String gender;
    @Column
    private String maritialStatus;

    @MapsId
    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "empid", referencedColumnName = "empid")
    @ForeignKey(name="empid")
    private Employee employee;

//getter setters

@RequestMapping(value="addpersonal")
    public ModelAndView addPersonalDetails(@ModelAttribute("personalDetails") PersonalDetails personalDetails) {
        //personalDetails.setEmpid(1);
        personalDetails.setCurrentAddress("niljyoti");
        personalDetails.setMob("9405715872");
        personalDetails.setPermenantAdress("address");
        Employee e = empService.getEmployeebyUserName(uname);
        personalDetails.setEmployee(e);
        personalDetailsService.addPersonalDetails(personalDetails);
        return new ModelAndView("home");

    }

=====================================个人详细信息类====================

@Entity
@Table(name="employee")
public class Employee {
    @Id
    @Column
    @GeneratedValue
    private int empid;
    @Column
    private String firstName;
    @Column
    private String lastName;
    @Column
    private String email;
    @Column
    private String password;
    @Column
    private boolean isAdmin;

    @Column
    private boolean isActive;

    @Column
    private boolean isLocked;
//getter setters

@Entity
@Table(name="PersonalDetails")
public class PersonalDetails {
    @Column
    @Id
    private int empid;
    @Column
    private String personalEmail;
    @Column
    private String mob;
    @Column
    private String permenantAdress;
    @Column
    private String currentAddress;
    @Column
    private String gender;
    @Column
    private String maritialStatus;

    @MapsId
    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "empid", referencedColumnName = "empid")
    @ForeignKey(name="empid")
    private Employee employee;

//getter setters

@RequestMapping(value="addpersonal")
    public ModelAndView addPersonalDetails(@ModelAttribute("personalDetails") PersonalDetails personalDetails) {
        //personalDetails.setEmpid(1);
        personalDetails.setCurrentAddress("niljyoti");
        personalDetails.setMob("9405715872");
        personalDetails.setPermenantAdress("address");
        Employee e = empService.getEmployeebyUserName(uname);
        personalDetails.setEmployee(e);
        personalDetailsService.addPersonalDetails(personalDetails);
        return new ModelAndView("home");

    }

在“我的应用程序”表中，在创建新员工时，管理员用户会填写员工本人（通过登录到管理员创建的帐户填写个人详细信息表）

现在，当我尝试将个人详细信息bean发送到hibernate层时，首先我必须从employee表中获取employee bean，然后通过personalDetails类调用setEmployee方法，将employee bean保存在personalDetails中，并发送到hibernate层以保存在数据库中

所以，当从数据库中获取Employeebean并再次通过personalDetails返回时，bean会导致性能问题

在将数据保存在子表（PersonalDetails）中时，是否有人可以帮助澄清传递父对象（Employee）是否确实是必需的

===============================存储个人详细信息的代码===============

@Entity
@Table(name="employee")
public class Employee {
    @Id
    @Column
    @GeneratedValue
    private int empid;
    @Column
    private String firstName;
    @Column
    private String lastName;
    @Column
    private String email;
    @Column
    private String password;
    @Column
    private boolean isAdmin;

    @Column
    private boolean isActive;

    @Column
    private boolean isLocked;
//getter setters

@Entity
@Table(name="PersonalDetails")
public class PersonalDetails {
    @Column
    @Id
    private int empid;
    @Column
    private String personalEmail;
    @Column
    private String mob;
    @Column
    private String permenantAdress;
    @Column
    private String currentAddress;
    @Column
    private String gender;
    @Column
    private String maritialStatus;

    @MapsId
    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "empid", referencedColumnName = "empid")
    @ForeignKey(name="empid")
    private Employee employee;

//getter setters

@RequestMapping(value="addpersonal")
    public ModelAndView addPersonalDetails(@ModelAttribute("personalDetails") PersonalDetails personalDetails) {
        //personalDetails.setEmpid(1);
        personalDetails.setCurrentAddress("niljyoti");
        personalDetails.setMob("9405715872");
        personalDetails.setPermenantAdress("address");
        Employee e = empService.getEmployeebyUserName(uname);
        personalDetails.setEmployee(e);
        personalDetailsService.addPersonalDetails(personalDetails);
        return new ModelAndView("home");

    }

宣读：

如果担心的话，您可以更改获取策略。 基于od JPA规范，

@OneToOne

的默认获取类型为

EAGER

通过设置

fetch=FetchType.LAZY

，而不是real

PersonalDetails

对象，将返回作为代理的子类的对象。因此，只有在调用了

getEmployee

之后，才能从

employee

表中进行选择

书面：

您需要指定实体之间的连接，在您的模型中，唯一的方法是

employee

字段。但是，您可以指定

mappedBy

，请参阅此问题的答案：

---

哪个代码导致了哪个性能问题？发布代码而不是描述它。