Sql server 2008 字符串连接的简化语句

我需要连接以下xml中的一些属性：

set @data = N'<properties>
                    <property>
                        <name>first</name>
                    </property>
                    <property>
                        <name>second</name>
                    </property>
                    <property>
                        <name>third</name>
                    </property>
                </properties>'

如果我要提取的结果是：first=#。first，second=#。second，third=#。third，我的解决方案如下所示：

declare mycursor cursor fast_forward
for select
    x.value(N'(name)[1]', N'nvarchar(50)')
from
    @data.nodes(N'/properties/property') AS xtbl(x)

declare @name nvarchar(50), @result nvarchar(max) = N'$name$=#.$name2$'

open mycursor
fetch next from mycursor into @name
while @@fetch_status = 0
begin               
    set @result= replace(@result, N'$name$', @name)
    set @result = replace(@result, N'$name2$', @name + N',$name$=#.$name2$')
    fetch next from mycursor into @name
end
close mycursor;
deallocate mycursor;

set @result = replace(@result, N',$name$=#.$name2$', '')

如何在不使用任何循环的情况下执行此操作？

您可以使用：

declare @result nvarchar(max)=''
select @result = @result + x.value(N'(name)[1]', N'nvarchar(50)') 
                         + '=#.' 
                         + x.value(N'(name)[1]', N'nvarchar(50)') 
                         + ','
from @data.nodes(N'/properties/property') as xtbl(X)   
select @result = left(@result, LEN(@result)-1)
print @result

您可以使用：

declare @result nvarchar(max)=''
select @result = @result + x.value(N'(name)[1]', N'nvarchar(50)') 
                         + '=#.' 
                         + x.value(N'(name)[1]', N'nvarchar(50)') 
                         + ','
from @data.nodes(N'/properties/property') as xtbl(X)   
select @result = left(@result, LEN(@result)-1)
print @result