Sql server SQL Server时间表查询

我需要一个查询和数据来生成时间表

我目前的查询如下：

SELECT contract.lect_code code1,
       contract.coll_code code2,
       line_date,
       start_time,
       end_time,
       DATEPART(DW,line_date) AS day_number,
       datename (dw,line_date) AS nameofday,
       convert(varchar(8),start_time,108) AS start_time2,
       convert(varchar(8),end_time,108) AS end_time2
FROM bk_line
INNER JOIN contract ON contract.contract_no = bk_line.contract_no
WHERE line_date BETWEEN '2013/09/23' AND '2013/09/27'
  AND coll_code = 'TEL01'
  AND bk_line_status = 'CE'
--And lect_code = 10430973 

这为我提供了以下格式的数据：

我需要一种方法，将时间分解为每个代码1和行日期15分钟的时段

大概是这样的：

;with t as
 (
 select cast('00:00:00' as time) as intStart,
 0 as l
 union all
 select DATEADD(MINUTE, 15,intStart),
 l+1
 from t
 where intStart<='23:30:00'
 )
select * 
from t;

代码1 |代码2 |行|日期| 0900工作| 0915工作| 0930工作|

其中0900worked中的值为T或F

-

编辑

---

我需要按代码1和行日期对时段进行分组。因此，在上述示例中，1045096在2013/09/25工作了两次。我需要两个会话显示在同一行，并计算所有时段。

可以使用以下内容创建一个间隔表：

select  case
        when convert(varchar(8),end_time,108) >= '09:15:00'
             and convert(varchar(8),start_time,108) <= '09:00:00' 
             then 'T'
             else 'F'
        end as [0900worked]
,       case
        when convert(varchar(8),end_time,108) >= '09:30:00'
             and convert(varchar(8),start_time,108) <= '09:15:00' 
             then 'T'
             else 'F'
        end as [0915worked]
,       ...

;with t as
 (
 select cast('00:00:00' as time) as intStart,
 0 as l
 union all
 select DATEADD(MINUTE, 15,intStart),
 l+1
 from t
 where intStart<='23:30:00'
 )
select * 
from t;

然后，您可以使用它连接到您的数据，并提供查看白天15分钟间隔中任何一个间隔的范围

---

然后，您可以对任何间隔使用Andomar的select语句。

可以使用以下内容创建间隔表：

;with t as
 (
 select cast('00:00:00' as time) as intStart,
 0 as l
 union all
 select DATEADD(MINUTE, 15,intStart),
 l+1
 from t
 where intStart<='23:30:00'
 )
select * 
from t;

然后，您可以使用它连接到您的数据，并提供查看白天15分钟间隔中任何一个间隔的范围

---

然后，您可以对任何时间间隔使用Andomar的select语句。

您可以这样做，但我认为有更好的方法来检查某人是否在给定的时间间隔内工作

with "nums"
as
(
  select 1 as "value"
  union all select "value" + 15 as "value"
  from "nums"
  where "value" <= 95*15
)
, "intervals"
as
(
  select
  "id" = "value" / 15
  , "startDate" =  dateadd( minute, "value" -1 , dateadd(year, datediff(year, 0, getdate()), 0))
  , "endDate" =  dateadd( minute, "value" + 14, dateadd( year, datediff( year, 0, getdate()), 0 ))

from
  "nums"
)
,"matched"
as
(
select 
    I.*
    , D."id" as "code1" 
from 
    intervals as I
left join "data" as D
    on D."startDate" <= I."startDate"
    and D."endDate" >= I."endDate"
)   
select
*
from
(
  select
    "code1"
    , "startDate"
  from
    "matched"
) as Data
  pivot( count(Data."startdate") 
  for "startDate" 
  in (  "2013-01-01 00:00:00.000"
      , "2013-01-01 00:15:00.000" 
      , "2013-01-01 00:30:00.000" 
      , "2013-01-01 00:45:00.000" 
      , "2013-01-01 01:00:00.000" 
      , "2013-01-01 01:15:00.000" 
      , "2013-01-01 01:30:00.000" 
      , "2013-01-01 01:45:00.000" 
      , "2013-01-01 02:00:00.000" 
      , "2013-01-01 02:15:00.000" 
      , "2013-01-01 02:30:00.000" 
     )) as p
where p.code1 is not null

---

你可以这样做，但我认为有更好的方法来检查某人是否在给定的时间间隔内工作

with "nums"
as
(
  select 1 as "value"
  union all select "value" + 15 as "value"
  from "nums"
  where "value" <= 95*15
)
, "intervals"
as
(
  select
  "id" = "value" / 15
  , "startDate" =  dateadd( minute, "value" -1 , dateadd(year, datediff(year, 0, getdate()), 0))
  , "endDate" =  dateadd( minute, "value" + 14, dateadd( year, datediff( year, 0, getdate()), 0 ))

from
  "nums"
)
,"matched"
as
(
select 
    I.*
    , D."id" as "code1" 
from 
    intervals as I
left join "data" as D
    on D."startDate" <= I."startDate"
    and D."endDate" >= I."endDate"
)   
select
*
from
(
  select
    "code1"
    , "startDate"
  from
    "matched"
) as Data
  pivot( count(Data."startdate") 
  for "startDate" 
  in (  "2013-01-01 00:00:00.000"
      , "2013-01-01 00:15:00.000" 
      , "2013-01-01 00:30:00.000" 
      , "2013-01-01 00:45:00.000" 
      , "2013-01-01 01:00:00.000" 
      , "2013-01-01 01:15:00.000" 
      , "2013-01-01 01:30:00.000" 
      , "2013-01-01 01:45:00.000" 
      , "2013-01-01 02:00:00.000" 
      , "2013-01-01 02:15:00.000" 
      , "2013-01-01 02:30:00.000" 
     )) as p
where p.code1 is not null

---

+如果以十次间隔为准，1个点可能是一个大问题……但假设这就是beast的本质，谢谢。我已经将它添加到我的代码中，它工作得很好。我还有一个问题。我会把它作为编辑贴出来。你可以把箱子放在maxcase里。。。结束时为[0900已工作]。因为'T'>'F'，如果组中的任何一行包含9:00-9:15的时间间隔，则返回true。谢谢。我把上面的内容放在一个CTE中，然后对每一个区间使用max。如果是十个区间，+1点……可能是一个大问题……但是假设这就是beast的性质谢谢。我已经将它添加到我的代码中，它工作得很好。我还有一个问题。我会把它作为编辑贴出来。你可以把箱子放在maxcase里。。。结束时为[0900已工作]。因为'T'>'F'，如果组中的任何一行包含9:00-9:15的时间间隔，则返回true。谢谢。我把上面的内容放在一个CTE中，然后对每个区间使用max。Query给出了0和1，而不是T和F，但是当Query给出了0和1，而不是T和F时，你可以很容易地放一个case，但是当你在它周围时，你可以很容易地放一个case