使用Sql Server从完整路径解析Html文件名
在以下示例中,我需要从Sql Server SELECT语句中的完整路径解析HTML文件名:使用Sql Server从完整路径解析Html文件名,sql,sql-server,sql-server-2016,Sql,Sql Server,Sql Server 2016,在以下示例中,我需要从Sql Server SELECT语句中的完整路径解析HTML文件名: Declare @x table(Id int primary key, form_url varchar(256)) Insert @x values (1, 'Agents/Accounting/Agent.html') Insert @x values (2, 'Modules/Vendors/Vendors/VendorInformation/Vendor.html') Insert
Declare @x table(Id int primary key, form_url varchar(256))
Insert @x values (1, 'Agents/Accounting/Agent.html')
Insert @x values (2,
'Modules/Vendors/Vendors/VendorInformation/Vendor.html')
Insert @x values (3,
'Modules/Customers/Customers/AccountInformation/Account.html?AccountNo')
Select * from @x
注意:路径之间的级别数量可变,HTML文件名后面可能有数据
我想要的输出是:
- Agent.html
- Vendor.html
- Account.html
reverse
和charindex
将所有内容设置为最后一个斜杠,然后使用charindex
或子字符串
仅限制HTML页面
Declare @x table(Id int primary key, form_url varchar(256))
Insert @x values (1, 'Agents/Accounting/Agent.html')
Insert @x values (2,
'Modules/Vendors/Vendors/VendorInformation/Vendor.html')
Insert @x values (3,
'Modules/Customers/Customers/AccountInformation/Account.html?AccountNo')
Select
*
,FullPath = right(form_url,charindex('/',reverse(form_url)) - 1)
,OnlyHtml = left(right(form_url,charindex('/',reverse(form_url)) - 1) ,charindex('.html',right(form_url,charindex('/',reverse(form_url)) + 3)))
,AnotherOnlyHtml = right(substring(form_url,1,charindex('.html',form_url) + 4),charindex('/',reverse(substring(form_url,1,charindex('.html',form_url) + 4))) - 1)
from @x
T-SQL不是为字符串操作而设计的。但有可能实现您所需要的:
Select x.*, IIF(CHARINDEX('?', sub.s) > 0,
LEFT(sub.s, CHARINDEX('?', sub.s)-1),
sub.s) result
from @x x
CROSS APPLY (SELECT IIF(CHARINDEX('/',form_url) > 0,
RIGHT(form_url,CHARINDEX('/', REVERSE(form_url))-1),
form_url)) sub(s);
如果对助手函数感兴趣。这是一个经过修改的parse/split函数,它接受两个不相似的delimeter。在您的情况下,可以是
“/”
和“?”
。你可能注意到了一个附加的“?”以防你遗漏了一个
示例
Select *
From @x
Cross Apply [dbo].[tvf-Str-Extract](form_url+'?','/','?') B
感兴趣的功能
CREATE FUNCTION [dbo].[tvf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (
Select *,RetVal = Substring(@String, N, L)
From cte4
) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[tvf-Str-Extract] (@String,'[[',']]')
*/