Sql 如何合并同一列中具有相同数据的多行?
我的密码是:Sql 如何合并同一列中具有相同数据的多行?,sql,sql-server,sql-server-2008,subquery,Sql,Sql Server,Sql Server 2008,Subquery,我的密码是: SELECT datepart(year, request_created_date) AS request_year, datepart(month, request_created_date) AS request_month, datepart(week, request_created_date) AS request_week, count(request_id) AS request_count FROM nyc311_requests GROU
SELECT datepart(year, request_created_date) AS request_year,
datepart(month, request_created_date) AS request_month,
datepart(week, request_created_date) AS request_week,
count(request_id) AS request_count
FROM nyc311_requests
GROUP BY request_created_date
ORDER BY request_week
在我得到的输出中,我有两行,其中request_week为36,还有7行,其中request_week为37。我想要的是将这样的列合并成一行 如果要使用GROUP BY子句,则必须包括GROUP BY中除计算字段以外的所有字段:
SELECT datepart(year, request_created_date) AS request_year,
datepart(month, request_created_date) AS request_month,
datepart(week, request_created_date) AS request_week,
count(request_id) AS request_count
FROM nyc311_requests
GROUP BY datepart(year, request_created_date),
datepart(month, request_created_date),
datepart(week, request_created_date)
ORDER BY request_week
或者,如果您想要一个更干净的查询:
SELECT M.*, count(*) AS request_count FROM
(
SELECT datepart(year, request_created_date) AS request_year,
datepart(month, request_created_date) AS request_month,
datepart(week, request_created_date) AS request_week
FROM nyc311_requests
)AS M
GROUP BY M.request_year, M.request_month, M.request_week
ORDER BY M.request_week
您是否尝试过将分组依据更改为
GROUP BY datepart(周,请求创建日期)
是的,但我收到一个错误消息,说请求创建日期无效,因为它不是聚合或在GROUP BY子句中。以下情况如何:GROUP BY datepart(年,请求创建日期),datepart(月,请求创建日期),datepart(周,请求创建日期)