从单元格中选择特定信息，包括其他信息SQL Server 2008 R2_Sql_Sql Server

从单元格中选择特定信息，包括其他信息SQL Server 2008 R2

sql sql-server

从单元格中选择特定信息，包括其他信息SQL Server 2008 R2,sql,sql-server,Sql,Sql Server,我试图从一个变量中选择特定的信息，我将在下面解释这个场景 CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX)) RETURNS @returnList TABLE ([Name] [nvarchar] (500)) AS BEGIN DECLARE @name NVARCHAR(255) DECLARE @pos INT declare @l

我试图从一个变量中选择特定的信息，我将在下面解释这个场景

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

模块向my db中的日志记录过程提供数据，并将其插入表中，例如：

IF(@EventID = 20)
BEGIN
    INSERT INTO _LogPvps 
    VALUES (@CharID, @Desc)
END

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

在

@Desc

中有一个包含3个变量的文本字符串，我需要将其提取并添加到另一个表中，字符串示例：（变量1,2,3）

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

我可以像这样通过1个变量进行拆分，但如果可能的话，我需要能够区分所有3个变量

IF @Desc LIKE '%My: Hunter, Neutral, no freebattle team%%His%%, Neutral, no freebattle team%%'
 BEGIN
     DECLARE @CNAME VARCHAR (64)
     DECLARE @JOB VARCHAR (16)

     SET @CNAME = (SELECT CHARNAME16 FROM DB_TEST.._Char WHERE CHARID = @CHARID) 
     SET @JOB = 'Hunter'

     INSERT INTO JOBKILLS 
     VALUES (@CHARID, @CNAME, @JOB, CURRENT_TIMESTAMP, @Desc)
 END

 IF @Desc LIKE '%My: Robber, Neutral, no freebattle team%%His%%, Neutral, no freebattle team%%'
 BEGIN
     DECLARE @CNAME VARCHAR (64)
     DECLARE @JOB VARCHAR (16)

     SET @CNAME = (SELECT CHARNAME16 FROM DB_TEST.._Char WHERE CHARID = @CHARID) 
     SET @JOB = 'Thief'

     INSERT INTO JOBKILLS 
     VALUES (@CHARID, @CNAME, @JOB, CURRENT_TIMESTAMP, @Desc)
 END

 IF @Desc LIKE '%My: Trader, Neutral, no freebattle team%%His%%, Neutral, no freebattle team%%'
 BEGIN
     DECLARE @CNAME VARCHAR (64)
     DECLARE @JOB VARCHAR (16)

     SET @CNAME = (SELECT CHARNAME16 FROM DB_TEST.._Char WHERE CHARID = @CHARID) 
     SET @JOB = 'Trader'

     INSERT INTO JOBKILLS 
     VALUES (@CHARID, @CNAME, @JOB, CURRENT_TIMESTAMP, @Desc)
 END

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

那么，我如何才能选择每个变量，从而不能将它们设置为标量变量，并将它们插入到单独表中的各个列中呢

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

例如：

INSERT INTO JOBKILLS 
VALUES (@CHARID, @CNAME, @JOB,
        @variant1, @variant2, @variant3,
        CURRENT_TIMESTAMP, @Desc)

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

另一种解释方式是，A-B-C根据用户ingame的操作而变化，我需要从@Desc字符串中选取所有3个，并将它们放在另一个表中的单独列中

[My: **A**, Neutral, no freebattle team] [His(**B**): **C**, Neutral, no freebattle team]

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

在我看来，这似乎是一个将字符串拆分为多个部分，然后将它们添加到表中的问题。这个问题已经解决了好几次了。但是，如果问题与此不同，那么请添加一些进一步的细节，说明为什么您的问题是唯一的。下面是拆分字符串并返回表的代码。不用说，您可能需要修改它以满足您的特定需求

CREATE FUNCTION [dbo].[splitstring] ( @stringToSplit VARCHAR(MAX), @delim VARCHAR(MAX))
RETURNS
    @returnList TABLE ([Name] [nvarchar] (500))

AS
BEGIN
    DECLARE @name NVARCHAR(255)
    DECLARE @pos INT
    declare @len int = len(@delim)
    declare @nextchar int = 1
    declare @startofstring int = 1
    WHILE CHARINDEX(@delim, @stringToSplit) > 0
    BEGIN
        SELECT @pos  = CHARINDEX(@delim, @stringToSplit)  
        SELECT @name = SUBSTRING(@stringToSplit, @startofstring, @pos-@nextchar)

        INSERT INTO @returnList 
        SELECT @name

        SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+@nextchar+@len, LEN(@stringToSplit)-@pos)
    END
    INSERT INTO @returnList
    SELECT @stringToSplit

    RETURN
END

GO

抱歉，无法理解

变体

零件。你能用一种更简单的方式来描述它吗？a-B-C的变化取决于用户ingame所做的事情，我需要从@Desc字符串中选取所有3个，并将它们放在另一个表中的单独列中。[我的：A，中立，没有自由战斗队][他的（B）：C，中立，没有自由战斗队]嗨，在我看来，把这个字符串分成几个部分，然后将它们添加到表中是一个问题。这个问题已经解决了好几次了。但是，如果问题与此不同，那么请添加一些进一步的细节，说明为什么您的问题是唯一的。下面是拆分字符串并返回表的代码。