SQL Server:将同一行中的2列分组

我有这个疑问

select 
    Id,
    case when isThirdParty = 0 then sum(total) end as FirstPartyFees,
    case when isThirdParty = 1 then sum(total) end as ThirdPartyFees
from 
    MyTable
group by 
    id, isThirdParty

我得到了这个结果

Id                                    FirstPartyFees                          ThirdPartyFees
------------------------------------ --------------------------------------- ---------------------------------------
DA29BDC0-BE3F-4193-BFDC-493B354CE368 15.00                                   0.00
2EF0B590-FE4F-42E8-8426-5864A739C16B 5.00                                    0.00
246DC3D8-732F-4AE3-99F3-BDEBF98F7719 15.00                                   0.00
FC81F220-ED54-48FE-AE1B-C394492E82A4 5.00                                    0.00
336D9CF1-6970-48BA-90E5-C7889914DDCB 114.00                                  0.00
6F2EEF6F-5FA1-42E5-A988-DB88037DAB92 5.00                                    0.00
80763B37-68E1-4716-B32A-FE82C1700B52 15.00                                   0.00
DA29BDC0-BE3F-4193-BFDC-493B354CE368 0.00                                    1.00
2EF0B590-FE4F-42E8-8426-5864A739C16B 0.00                                    1.00
246DC3D8-732F-4AE3-99F3-BDEBF98F7719 0.00                                    1.00
FC81F220-ED54-48FE-AE1B-C394492E82A4 0.00                                    1.00
336D9CF1-6970-48BA-90E5-C7889914DDCB 0.00                                    0.00
6F2EEF6F-5FA1-42E5-A988-DB88037DAB92 0.00                                    1.00
80763B37-68E1-4716-B32A-FE82C1700B52 0.00                                    1.00

---

如你所见，我为第一方和第三方提供了副本。如何在一行中对同一Id的第一方和第三方合计进行分组？

您正在寻找条件聚合

您应该将大小写表达式移到sum中，并从GROUPBY子句中删除isThirdParty

因为iThirdParty是一个指标，所以您也可以使用数学：

select Id, SUM(total * (1 - isThirdParty)) as FirstPartyFees,
   SUM(total * isThirdParty) as ThirdPartyFees
frOm MyTable
group by id;

---

你对这么快的答案投了赞成票。我迟到了30秒：-@TimBiegeleisen:谢谢。。。我从你和其他SQL大师那里学到了速度在这里如此重要的艰难过程。。。

select Id, SUM(total * (1 - isThirdParty)) as FirstPartyFees,
   SUM(total * isThirdParty) as ThirdPartyFees
frOm MyTable
group by id;