SQL查询选择每个员工的每种表单类型

我使用的是MSSQL server 2008，有两个表

表单

和

员工

表单

包含员工填写的所有表单，例如

[id][employeeId][formId]

只有6种类型的表单，每种表单都有自己的id。我如何构造一个查询来列出每种类型表单的每位员工，以及这些表单是否已完成（存在于

表单
表中），例如

编辑：我的当前查询，列出所有需要“过滤”到上面架构的信息：

SELECT  *
FROM forms as f
inner join employees as e on e.EmployeeID = f.EmployeeID

也许这能奏效

SELECT emp.[employeeName], form1.formId as formType1, form2.formId as formType2, form3.formId as formType3, form4.formId as formType4, form5.formId as formType5, form6.formId as formType6 
FROM [database_name].dbo.[employees] as emp 
RIGHT OUTER JOIN [database_name].dbo.[form] as form1 ON (emp.[EmployeeID] = form1.[EmployeeID] AND form1.id='ID_FOR_THE_FORM1') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form2 ON (emp.[EmployeeID] = form2.[EmployeeID] AND form2.id='ID_FOR_THE_FORM2') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form3 ON (emp.[EmployeeID] = form3.[EmployeeID] AND form3.id='ID_FOR_THE_FORM3') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form4 ON (emp.[EmployeeID] = form4.[EmployeeID] AND form4.id='ID_FOR_THE_FORM4') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form5 ON (emp.[EmployeeID] = form5.[EmployeeID] AND form5.id='ID_FOR_THE_FORM5') 
RIGHT OUTER JOIN [database_name].dbo.[form] as form6 ON (emp.[EmployeeID] = form6.[EmployeeID] AND form6.id='ID_FOR_THE_FORM6') ;

不完全是你在寻找什么，你可以求值如果为空，那么员工不回答其他形式的问题，他回答它。我希望这有助于
您可以根据员工ID进行分组，并“计算”每种表单类型的实例数：

SELECT  employeeid,
    SUM(CASE WHEN f.ID = 1 THEN 1 ELSE 0 END) formType1,
    SUM(CASE WHEN f.ID = 2 THEN 1 ELSE 0 END) formType2,
    SUM(CASE WHEN f.ID = 3 THEN 1 ELSE 0 END) formType3,
    SUM(CASE WHEN f.ID = 4 THEN 1 ELSE 0 END) formType4,
    SUM(CASE WHEN f.ID = 5 THEN 1 ELSE 0 END) formType5,
    SUM(CASE WHEN f.ID = 6 THEN 1 ELSE 0 END) formType6
FROM forms as f
GROUP BY employeeid

如果您也希望看到未填写任何表格的员工，您可以尝试以下方法：

Select FormName, EmpName, id
FROM 
    (SELECT formID ,FormName , empID, EmpName
            FROM FormTypes  
                CROSS JOIN Emp) x
        LEFT JOIN Forms f on (x.empid = f.employeename and  x.formID = f.formID) 

你可以发布你现在使用的选择吗？如果我could@Lee听了你的评论，D Stanley，我想这比我的答案更有效，因为我的答案是，你在同一个表实例上执行所有操作。。。很高兴看到同样的新方法，太好了！
Select FormName, EmpName, id
FROM 
    (SELECT formID ,FormName , empID, EmpName
            FROM FormTypes  
                CROSS JOIN Emp) x
        LEFT JOIN Forms f on (x.empid = f.employeename and  x.formID = f.formID)