Sql 将多个“WITH CTE”查询的结果作为一个结果返回

我试图在n个时间段内从同一产品中选择最高价格，即最后5、50、100、500。 目前，我正在为上述时间段运行四次查询，如下所示：

;WITH CTE AS 
(
    SELECT TOP (500) * FROM Ticker WHERE ProductId='BTC-USD'
    ORDER BY ID DESC
)  SELECT TOP (1) * FROM CTE 
ORDER BY PRICE desc

---

有没有办法一次在4行中获得所有结果？

Hmmmm。我的第一个想法是建立一个联盟：

但是，我有另一个想法：

with cte as (
      select top (500) t.*, row_number() over (order by id desc) as seqnum
      from Ticker t
      where ProductId = 'BTC-USD'
      order by id desc
     )
select v.which, x.max_price
from (values (5), (50), (100), (500)) v(which) cross apply
     (select max(price) as max_price from cte where seqnum <= which) x;

当然，CTE中的500需要与v中的最大值相匹配。实际上，你可以去掉CTE中的顶部

with cte as (
      select top (500) t.*, row_number() over (order by id desc) as seqnum
      from Ticker t
      where ProductId = 'BTC-USD'
      order by id desc
     )
select v.which, x.max_price
from (values (5), (50), (100), (500)) v(which) cross apply
     (select max(price) as max_price from cte where seqnum <= which) x;